Power Systems What is the correct expression for the electrical power developed by 75 × 0.736 × WQHη. ( 7 / 75 ) × WQHη. ( 0.763 / 75 ) × WQHη. ( 75 / 0.736 ) × WQHη. 75 × 0.736 × WQHη. ( 7 / 75 ) × WQHη. ( 0.763 / 75 ) × WQHη. ( 75 / 0.736 ) × WQHη. ANSWER DOWNLOAD EXAMIANS APP
Power Systems The sequence components of the fault current are as follows: IR1 = j1.5 pu, IR2 = -j0.5 pu, IR0 = -j1. The type of fault is LLG LLL LG LL LLG LLL LG LL ANSWER DOWNLOAD EXAMIANS APP
Power Systems Nuclear power plant are used as intermediate load plants. base load plants. none of above. peak load plants. intermediate load plants. base load plants. none of above. peak load plants. ANSWER DOWNLOAD EXAMIANS APP
Power Systems Pelton wheel turbine is a high head turbine. medium head turbine. low head turbine. none of above. high head turbine. medium head turbine. low head turbine. none of above. ANSWER DOWNLOAD EXAMIANS APP
Power Systems Which of the following power plants needs highly skilled/qualified engineers for its operation Nuclear. Hydro Power Plant Thermal. Gas-turbine. Nuclear. Hydro Power Plant Thermal. Gas-turbine. ANSWER DOWNLOAD EXAMIANS APP
Power Systems An over current relay, having a current setting of 125% connected to a supply circuit through a current transformer of ratio 500/5. The plug setting multiplier for a fault current of 5 kA is 8 2 6 5 8 2 6 5 ANSWER DOWNLOAD EXAMIANS APP
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