Applied Mechanics and Graphic Statics ‘ω’ rad/sec is the angular velocity of a crank whose radius is ‘r’. If it makes θ° with inner dead centre and obliquity of the connecting rod ‘l’ is ‘ϕ’, the velocity v of the piston, is given by the equation ω² (l sin ϕ - r cos θ tan ϕ) ω (l sin ϕ + r cos ϕ tan θ) ω² (l sin ϕ + r cos φ tan θ) ω² (l cos ϕ + r sin ϕ tan θ) ω² (l sin ϕ - r cos θ tan ϕ) ω (l sin ϕ + r cos ϕ tan θ) ω² (l sin ϕ + r cos φ tan θ) ω² (l cos ϕ + r sin ϕ tan θ) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body slides down an inclined surface, the acceleration (f) of the body, is given by f = g f = g sin θ f = g cos θ f = g tan θ f = g f = g sin θ f = g cos θ f = g tan θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The motion of a particle is described by the relation x = t²- 10t + 30, where x is in meters and t in seconds. The total distance travelled by the particle from t = 0 to t = 10 seconds would be 30 m 50 m Zero 60 m 30 m 50 m Zero 60 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of a triangle is at the point where three Medians of the triangle meet Bisectors of the angle of the triangle meet Perpendicular bisectors of the sides of the triangle meet None of these Medians of the triangle meet Bisectors of the angle of the triangle meet Perpendicular bisectors of the sides of the triangle meet None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The necessary condition of equilibrium of a body is: Algebraic sum of the moments of the forces about a point must be zero All (A), (B) and (C) Algebraic sum of vertical components of all the forces must be zero Algebraic sum of horizontal components of all the forces must be zero Algebraic sum of the moments of the forces about a point must be zero All (A), (B) and (C) Algebraic sum of vertical components of all the forces must be zero Algebraic sum of horizontal components of all the forces must be zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A cable loaded with 0.5 tonne per horizontal metre span is stretched between supports in the same horizontal line 400 m apart. If central dip is 20 m, the minimum tension in the cable, will be 200 tonnes at the centre 200 tonnes at the left support 200 tonnes at the right support 500 tonnes at the centre 200 tonnes at the centre 200 tonnes at the left support 200 tonnes at the right support 500 tonnes at the centre ANSWER DOWNLOAD EXAMIANS APP
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