Applied Mechanics and Graphic Statics A disc of mass 4 kg, radius 0.5 m and moment of inertia 3 kg.m² rolls on a horizontal surface so that its center moves with speed 5 m/see. Kinetic energy of the disc is 200 J 400 J 150 J 50 J 200 J 400 J 150 J 50 J ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The angular speed of a car while taking a circular turn of radius 100 m at 36 km/hour, is 0.1 radian/sec 100 radian/sec 1000 radian/sec 1 radian/sec 0.1 radian/sec 100 radian/sec 1000 radian/sec 1 radian/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The equation of motion of a particle starting from rest along a straight line is x = t³ - 3t²+ 5. The ratio of the accelerations after 5 sec and 3 sec will be 3 4 5 2 3 4 5 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball is dropped from a height of 16 m on a horizontal floor. If it rebounds to a height of 9 m after striking the floor, the coefficient of restitution between ball and floor is 43834 43894 43924 43864 43834 43894 43924 43864 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The dimensions of power are. M’L-‘T* M’L’T3 M’L’r2 M’L2T2 M’L-‘T* M’L’T3 M’L’r2 M’L2T2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ ANSWER DOWNLOAD EXAMIANS APP
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