Applied Mechanics and Graphic Statics A disc of mass 4 kg, radius 0.5 m and moment of inertia 3 kg.m² rolls on a horizontal surface so that its center moves with speed 5 m/see. Kinetic energy of the disc is 150 J 200 J 400 J 50 J 150 J 200 J 400 J 50 J ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The C.G. of a right circular cone lies on its axis of symmetry at a height of h/3 h/5 h/2 h/4 h/3 h/5 h/2 h/4 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘P’ is the force acting on a body whose mass is ‘m’ and acceleration is ‘f’. The equation P - mf= 0, is known as Equation of dynamics Equation of statics None of these Equation of dynamic equilibrium Equation of dynamics Equation of statics None of these Equation of dynamic equilibrium ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The piston of a steam engine moves with a simple harmonic motion. The crank rotates 120 r.p.m. and the stroke length is 2 meters. The linear velocity of the piston when it is at a distance of 0.5 metre from the centre, is 8.88 m/sec 12.88 m/sec 5.88 m/sec 10.88 m/sec 8.88 m/sec 12.88 m/sec 5.88 m/sec 10.88 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The masses of two balls are in the ratio of 2 : 1 and their respective velocities are in the ratio of 1 : 2 but in opposite direction before impact. If the coefficient of restitution is ½, the velocities of separation of the balls will be equal to Half the original velocity in the same direction Original velocity in the opposite direction Half the original velocity in the opposite direction Original velocity in the same direction Half the original velocity in the same direction Original velocity in the opposite direction Half the original velocity in the opposite direction Original velocity in the same direction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ - u₁ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ - u₁ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ ANSWER DOWNLOAD EXAMIANS APP
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