Fractions and Decimals Two times of the third of three consecutive even integers is three times of the first. Then the second integer is 7 10 1 4 7 10 1 4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the consecutive three integers be X, X + 2 and X + 4Then, 2(X + 4) = 3XX = 8Now X + 2 = 10The required second integer is 10
Fractions and Decimals 3 / [ 3+ {(0.3 - 3.03) / (3 x 0.91)}] = ? 1.0 2.0 1.5 0.5 1.0 2.0 1.5 0.5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = 3 / [ 3+ {(0.3 - 3.03) / (3 x 0.91)}] = 3 / [3- { 273 / (3 x 91)}] = 3 / (3-1)= 3 / 2 = 1.5
Fractions and Decimals If 5/6 of a property worth be Rs.976500 then the value of 3/5 of the property is: Rs. 803080 Rs. 903080 Rs. 703080 None of these Rs. 803080 Rs. 903080 Rs. 703080 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the worth of total property be Rs.XWe have to find 3/5 of X.Given that, 5/6 th of the property = Rs.976500i.e., 5/6 x X = 976500X = 976500 x 6/5And, 3/5 of X = 3/5 x 976500 x 6/5 = 18 x 39060 = 703080Hence the answer is Rs. 703080
Fractions and Decimals 999.99 + 25.012 = ? - 174.469 215 14 56 116 215 14 56 116 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? = (999.99)/25.012 + 174.469 = (1000/25) + 174.469= (40 + 174.469) = 214.469 = 215
Fractions and Decimals [ .6 x .6 x .6 x .4 x .4 x .4 + 3 x .6 x .4 x (.6 + .4 )] = ? 2 4 3 1 2 4 3 1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression =(.6)³ + (.4) ³ + 3 x .6 x .4 x (.6 + .4)= a³ + b³ + 3ab (a+b) = (a+b)³= (.6 + .4)³ = 1³ = 1
Fractions and Decimals (.538 x .538 - .462 x .462) / (1-.924) = ? 1 31 11 21 1 31 11 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [ (.538)² - (.462)² ] / .076 = [(.538 + .462)(.538 - .462)] /.076=.076 / .076 = 1
EXAMIANS