We have to find, the value of 4/7 of 560 - 5/8 of 400.4/7 x 560 - 5/8 x 400 = (4 x 80) - (5 x 50) = 320 - 250 = 70Hence, four-seventh of 560 is greater than five-eighth of 400 by 70.
Converting the given fractions into decimal form, we have,8/9 = 0.8818/23 = 0.7816/21 = 0.7614/17 = 0.82From the above, 0.88 is the largest.Corresponding fraction is 8/9.
Time required for service before overhauling = 2/3h = 40 min in 45 days and time required for service after overhauling =2/3h= 40 min in 60 days Now,LCM of 45 and 60 = 180 days time required for service before overhauling is 180 days = 40 x 4 = 160 min and time required for service before overhauling is 180 days =40 x 3 = 120 min ∴ fraction of time saved = 160 - 120/160 =40/160 = 1/4
EXAMIANS