Fractions and Decimals If the numerator of a fraction is increased by 2 and the denominator is increased by 1, the fraction because 5/8 and if the numerator of the same fraction is increased by 3 and the denominator is incr 2/7 1/7 4/7 3/7 2/7 1/7 4/7 3/7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the original fraction be p/q Then, (p + 2) / (q + 1) = 5/8⇒ 8p - 5q = 11 .....(i)Again (p + 3) / (q + 1) = 3/4⇒ 4p - 3q = 9 ...(ii)Solving equations , (i) and (ii), we get ,p = 3 and q = 7∴ Fraction = 3/7
Fractions and Decimals (.23 - .023) / ( .0023 / 23 ) = ? 2770 2070 2077 207 2770 2070 2077 207 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = (.23 - .023) / ( .0023 / 23 ) = .207 / (.0023 / 23) = .207 / .0001=.2070 / .0001 = 2070
Fractions and Decimals [(3.537 - .948)² + (3.537 + .948)²] / [(3.537)² + (.948)²] = ? 2 3 1 0 2 3 1 0 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(3.537 - .948)² + (3.537 + .948)²] / [(3.537)² + (.948)²] = [(a - b)² + (a + b)²] / (a²+ b²) (Where a = 3.537 and b = 0.948)= 2(a² +b²) / (a² +b²) = 2
Fractions and Decimals The rational for the recurring decimal 0.125125......is 125/99 125/9 None of these 125/999 125/99 125/9 None of these 125/999 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.125125...... = 0.125 = 125/999.
Fractions and Decimals If √4096 =64 ,then the value of √40.96 + √0.4096 + √0.004096 + √0.00004096 is ? 7.1104 .71104 71.104 711.04 7.1104 .71104 71.104 711.04 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP √4096/100+ √4096/10000 + √4096/1000000 + √4096/100000000=√4096 / 10 + √4096/ 100 + √4096/ 1000 + √4096/ 10000=64/10 + 64/100 + 64/1000 + 64/10000=6.4 + .64 + .064 + .0064 = 7.1104
Fractions and Decimals 9.724 ÷ 100 = ? 0.9724 9.724 None of these 0.09724 0.9724 9.724 None of these 0.09724 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 9.724 ÷ 100 = 0.09724Shift decimal two palaces to the left. i.e 100
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