Fractions and Decimals If the numerator of a fraction is increased by 2 and the denominator is increased by 1, the fraction because 5/8 and if the numerator of the same fraction is increased by 3 and the denominator is incr 3/7 1/7 4/7 2/7 3/7 1/7 4/7 2/7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the original fraction be p/q Then, (p + 2) / (q + 1) = 5/8⇒ 8p - 5q = 11 .....(i)Again (p + 3) / (q + 1) = 3/4⇒ 4p - 3q = 9 ...(ii)Solving equations , (i) and (ii), we get ,p = 3 and q = 7∴ Fraction = 3/7
Fractions and Decimals 50.8 / 2540 = ? 0.02 0.002 0.0002 None of these 0.02 0.002 0.0002 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 50.8 / 2540 = 508 / 25400 = 2 / 100 = .02
Fractions and Decimals (.538 x .538 - .462 x .462) / (1-.924) = ? 31 1 11 21 31 1 11 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [ (.538)² - (.462)² ] / .076 = [(.538 + .462)(.538 - .462)] /.076=.076 / .076 = 1
Fractions and Decimals If x/y = 0.3, then (2x - y)/(2x + y) = ? 0.5 0.25 0.15 0.5 0.5 0.25 0.15 0.5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP x = 0.3y Then, (y - 2x)/(y + 2x)= y - 2(0.3y)/y + 2(0.3y)= y - 0.6y/y + 0.6y= 0.4y/1.6y= 0.4/1.6 = 0.25
Fractions and Decimals (.125 + .027) / (.5 x .5 - 1.5 + .09) = ? 0.8 800 80 8 0.8 800 80 8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.5)³ + (0.3)³] / [(0.5)² - 0.5 x 0.3 + (0.3)²]= [a³ + b³] / [a² - ab + b²]=[(a + b)(a² - ab + b²)]/ [a² -ab + b²]= a+b = 0.5 + 0.3 = 0.8
Fractions and Decimals What should be subtracted from the multiplication of 0.527 and 2.013 to get 1 ? 6085.1 0.060851 None of these 60.851 6085.1 0.060851 None of these 60.851 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ∵ 0.527 x 2.013 = 1.060851Hence, the required number = 1.060851 - 1 = 0.060851.
EXAMIANS