Fractions and Decimals In the year 2011, Shantanu gets a total of Rs. 3832.5 as his pocket allowance. Find his pocket allowance per day.? Rs. 100.50 Rs. 1.50 Rs. 10.50 Rs. 1000.50 Rs. 100.50 Rs. 1.50 Rs. 10.50 Rs. 1000.50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Allowance per day = 3832.5 / 365 = Rs. 10.50
Fractions and Decimals Evaluate : [(2.39)² - (1.61)²] / [2.39 - 1.61] 6 2 4 3 6 2 4 3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression=(a² - b²) / (a - b)=[(a + b)(a - b)] / (a - b)= (a + b)= (2.39 + 1.61)= 4
Fractions and Decimals (10.3 * 10.3 * 10.3 + 1)/(10.3 * 10.3 - 10.3 + 1) is : 111.3 11.3 None of these 1.3 111.3 11.3 None of these 1.3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP a^3 + b^3 = (a+ b) * (a^2 + b^2 - ab)..( (10.3)^3 + (1)^3 ) / ((10.3)^2 + (1)^2 - (1 * 10.3))=> a + b = 10.3 + 1 = 11.3
Fractions and Decimals (.58 x .58 x .58 - .42 x .42 x .42 - 3 x .58 x .42 x .16) = ? 0.04096 4.096 0.004096 0.4096 0.04096 4.096 0.004096 0.4096 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression = (.53)³ - (.42)³- 3 x .58 x .42 x (.58-.42)= a³-b³ -3ab(a - b) = (a - b)³(where a = .58 and b=.42)= (.58 - .42 )³ = .16 x .16 x .16 = 0.004096
Fractions and Decimals What will come in place of question mark in the following equation ? 54.(?)3 + 543 + 5.43 = 603.26 8 7 5 3 8 7 5 3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let x + 543 + 5.43 = 603.26.Then, x = 603.26 - (543 + 5.43) = 603.26 - 548.43 =54.83Missing digit = 8.
Fractions and Decimals What should be subtracted from the multiplication of 0.527 and 2.013 to get 1 ? 60.851 0.060851 6085.1 None of these 60.851 0.060851 6085.1 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ∵ 0.527 x 2.013 = 1.060851Hence, the required number = 1.060851 - 1 = 0.060851.
EXAMIANS