Fractions and Decimals In the year 2011, Shantanu gets a total of Rs. 3832.5 as his pocket allowance. Find his pocket allowance per day.? Rs. 1000.50 Rs. 100.50 Rs. 1.50 Rs. 10.50 Rs. 1000.50 Rs. 100.50 Rs. 1.50 Rs. 10.50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Allowance per day = 3832.5 / 365 = Rs. 10.50
Fractions and Decimals (.356 x .365 - 2 x .365 x .106 + .106 x .106) / (.632 x .632 + 2 x .632 x .368 +.368 x .368) = ? 6.25 62.5 .625 .0625 6.25 62.5 .625 .0625 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(.356)² -2 x .356 x .106 + (.106)²] / [(.632)²+2 x .632 x .368 +(.368)²]= (a² -2ab + b²) / (c²+2cd+d²)= (a - b)² / (c + d)²= (.356 -.106)² / (.632 + .368)²= (.25)² = .0625
Fractions and Decimals The fraction ( 101 * 27/100000 ) in decimal form is : 10100.027. 101.00027 1010.0027 101000.27 10100.027. 101.00027 1010.0027 101000.27 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 101 * 27 / 100000 = 101 + 27 / 100000 = 101 + .00027 = 101.00027.
Fractions and Decimals [(0.1667)(0.8333)(0.3333)] / [(0.2222)(0.6667)(0.1250)] is approximately equal to: 4.50 2.50 1.50 3.50 4.50 2.50 1.50 3.50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression [(0.3333)/(0.2222)] x [((0.1667)(0.8333)) / ((0.6667)(0.1250))]=[(3333 / 2222)] x [((1/6) x (5/6)) / ((2/3) x (125/1000))]=[(3/2) x (1/6) x (5/6) x (3/2) x 8]=5 / 2=2.50
Fractions and Decimals [{(0.1)² - (0.01)²} / {0.0001 + 1 }] is equal to ? 100 25 75 50 100 25 75 50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = (0.01 - 0.0001) / (0.00001 + 1)= (.0099 / .0001) + 1 = 99 + 1= 100
Fractions and Decimals Two times of the third of three consecutive even integers is three times of the first. Then the second integer is 10 1 4 7 10 1 4 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the consecutive three integers be X, X + 2 and X + 4Then, 2(X + 4) = 3XX = 8Now X + 2 = 10The required second integer is 10
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