Fractions and Decimals In the year 2011, Shantanu gets a total of Rs. 3832.5 as his pocket allowance. Find his pocket allowance per day.? Rs. 10.50 Rs. 1000.50 Rs. 100.50 Rs. 1.50 Rs. 10.50 Rs. 1000.50 Rs. 100.50 Rs. 1.50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Allowance per day = 3832.5 / 365 = Rs. 10.50
Fractions and Decimals If two-third of two-seventh of a number is 60, then two-fifteenth of that number is 34 71 56 42 34 71 56 42 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the number be X.Then 2/3 x 2/7 x X =60X = 60 x 7 x 3 / 4 = 315Then, 2/15 of 315 = 2/15 x 315 = 42.Hence the required number is 42
Fractions and Decimals [( 3.242 x 14 ) / 100] = ? 0.045388 0.45388 4.5388 45.388 0.045388 0.45388 4.5388 45.388 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Multiplying 3.242 x 14=4.5388Now divide 4.5388 by 100So, 4.5388 ÷ 100= 0.045388∴ Shift the decimal two places to the left as 100
Fractions and Decimals If √4096 =64 ,then the value of √40.96 + √0.4096 + √0.004096 + √0.00004096 is ? 71.104 .71104 711.04 7.1104 71.104 .71104 711.04 7.1104 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP √4096/100+ √4096/10000 + √4096/1000000 + √4096/100000000=√4096 / 10 + √4096/ 100 + √4096/ 1000 + √4096/ 10000=64/10 + 64/100 + 64/1000 + 64/10000=6.4 + .64 + .064 + .0064 = 7.1104
Fractions and Decimals Which of the following fraction is arranged in ascending order of their value? 1/4, 2/7, 3/4, 4/7, 5/7, 6/5 2/7, 1/4, 4/7, 3/4, 5/7, 6/5 2/7, 1/4, 4/7, 5/7, 3/4, 6/5 1/4, 2/7, 4/7, 5/7, 3/4, 6/5 1/4, 2/7, 3/4, 4/7, 5/7, 6/5 2/7, 1/4, 4/7, 3/4, 5/7, 6/5 2/7, 1/4, 4/7, 5/7, 3/4, 6/5 1/4, 2/7, 4/7, 5/7, 3/4, 6/5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Converting the given fractions into decimal numbers, we have1/4 = 0.252/7 = 0.283/4 = 0.754/7 = 0.575/7 = 0.716/5 = 1.2So, 0.25 < 0.28 < 0.57 < 0.71 < 0.75 < 1.2Corresponding fraction is 1/4 < 2/7 < 4/7 < 5/7 < 3/4 < 6/5
Fractions and Decimals If 0.12 ÷ x² = 12, than x = ? 10 0.1 0.01 0.001 10 0.1 0.01 0.001 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.12 ÷ x² = 12 => 0.12/x² = 12=> x² = 0.12/12 = 0.01 => x = 0.1
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