Fractions and Decimals In the year 2011, Shantanu gets a total of Rs. 3832.5 as his pocket allowance. Find his pocket allowance per day.? Rs. 10.50 Rs. 1.50 Rs. 100.50 Rs. 1000.50 Rs. 10.50 Rs. 1.50 Rs. 100.50 Rs. 1000.50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Allowance per day = 3832.5 / 365 = Rs. 10.50
Fractions and Decimals If √5 = 2.24, then the value of 3√5 / 2√5 - 0.48 is ? 16.8 168 None of these 1.68 16.8 168 None of these 1.68 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = 3√5 / 2√5 - 0.48= (3 x 2.24) / (2 x 2.24) - 0.48= 6.72 / 4.48 - 0.48 = 6.72 / 4 = 1.68
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2012 2014 2011 2013 2012 2014 2011 2013 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Fractions and Decimals 0.002 * 0.5 = ? 1 0.1 0.001 0.01 1 0.1 0.001 0.01 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2 * 5 = 10.Sum of decimal places = 4..002 * .5 = 0.0010 = 0.001
Fractions and Decimals If 1.5 x a = 0.04 x b then the value of (b - a) / ( b + a) is ? 730/77 73/770 None of these 73/77 730/77 73/770 None of these 73/77 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP a / b = 0.04 / 1.5 = 4 / 150 = 2 / 75∴ Given Exp. (b - a) / ( b + a)= (1- a/b ) / (1 + a/b) = (1- 2 / 75) / (1 + 2 / 75)= ( 73/75 ) / ( 77/75)= 73/77
Fractions and Decimals 5 x 0.25 x 6.301 x 0.00394=? 0.0310324250 31.0324250 3.10324250 0.310324250 0.0310324250 31.0324250 3.10324250 0.310324250 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here 5 x 25 x 6301 x 394=310324250Total decimal places = (2+3+5) = 10 ∴ 5 x 0.25 x 6.301 x 0.00394 = 0.0310324250
EXAMIANS