Let the number be X Decreasing 2 from XX - 2 = 80 x (1/X)X^2 - 2X = 80X^2 -2x -80 = 0(X-10)(X+8) = 0x=10,-8X has two values, but among the given options X value should be 10
We have to find, the value of 4/7 of 560 - 5/8 of 400.4/7 x 560 - 5/8 x 400 = (4 x 80) - (5 x 50) = 320 - 250 = 70Hence, four-seventh of 560 is greater than five-eighth of 400 by 70.
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