Given expression [(0.3333)/(0.2222)] x [((0.1667)(0.8333)) / ((0.6667)(0.1250))]=[(3333 / 2222)] x [((1/6) x (5/6)) / ((2/3) x (125/1000))]=[(3/2) x (1/6) x (5/6) x (3/2) x 8]=5 / 2=2.50
Let the number be X Decreasing 2 from XX - 2 = 80 x (1/X)X^2 - 2X = 80X^2 -2x -80 = 0(X-10)(X+8) = 0x=10,-8X has two values, but among the given options X value should be 10
EXAMIANS