Fractions and Decimals If √4096 =64 ,then the value of √40.96 + √0.4096 + √0.004096 + √0.00004096 is ? 711.04 7.1104 .71104 71.104 711.04 7.1104 .71104 71.104 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP √4096/100+ √4096/10000 + √4096/1000000 + √4096/100000000=√4096 / 10 + √4096/ 100 + √4096/ 1000 + √4096/ 10000=64/10 + 64/100 + 64/1000 + 64/10000=6.4 + .64 + .064 + .0064 = 7.1104
Fractions and Decimals 3420 / 19 = ( ? / 0.01) x 7 9/30 9/40 9/45 9/35 9/30 9/40 9/45 9/35 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let 3420 / 19 = (y / 0.01) x 7Then , y = ( 3420 / 19) x (0.01 / 7) = 180 / 700 = 9/35
Fractions and Decimals [(3.537 - .948)² + (3.537 + .948)²] / [(3.537)² + (.948)²] = ? 0 2 1 3 0 2 1 3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(3.537 - .948)² + (3.537 + .948)²] / [(3.537)² + (.948)²] = [(a - b)² + (a + b)²] / (a²+ b²) (Where a = 3.537 and b = 0.948)= 2(a² +b²) / (a² +b²) = 2
Fractions and Decimals 3.5 + 21 x 1.3 = ? 24.8 28.8 30.8 26.8 24.8 28.8 30.8 26.8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression = 3.5 + 21 x 1.3 = 3.5 + 27.3 = Given Expression = 3.5 + 21 x 1.3 = 3.5 + 27.3 = 30.8
Fractions and Decimals By how much does 7/(8/9) exceeds (7/8)/9 ? 7 7/9 6 7/9 8 7/9 5 7/9 7 7/9 6 7/9 8 7/9 5 7/9 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here, we have to find the value of 7/(8/9) - (7/8)/9.(7 x 9/8) - [(7/(8 x 9)]63/8 - 7/72[(63 x 9) - 7] / 72567 - 7/72 = 560/72 = 70/9 = 7 7/9.Hence, 7/(8/9) is greater than (7/8)/9 by 7 7/9.
Fractions and Decimals If 0.12 ÷ x² = 12, than x = ? 0.01 0.001 0.1 10 0.01 0.001 0.1 10 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.12 ÷ x² = 12 => 0.12/x² = 12=> x² = 0.12/12 = 0.01 => x = 0.1
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