Fractions and Decimals If √4096 =64 ,then the value of √40.96 + √0.4096 + √0.004096 + √0.00004096 is ? 71.104 7.1104 .71104 711.04 71.104 7.1104 .71104 711.04 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP √4096/100+ √4096/10000 + √4096/1000000 + √4096/100000000=√4096 / 10 + √4096/ 100 + √4096/ 1000 + √4096/ 10000=64/10 + 64/100 + 64/1000 + 64/10000=6.4 + .64 + .064 + .0064 = 7.1104
Fractions and Decimals (.896 x .752 +.896 x .248) / (.7 x .034 + .7 x.966) = ? 1.33 1.28 1.31 1.25 1.33 1.28 1.31 1.25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = (.896 x .752 +.896 x .248) / (.7 x .034 + .7 x.966)=.[896 x (.752+.248)] / [.7 x (.034+.966)] = .(896 x 1) / ( .700 x 1)=896/700 = 1.28
Fractions and Decimals (0.16)² - (0.12)² = ? 11.2 1.12 .112 0.0112 11.2 1.12 .112 0.0112 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? = a² - b² = (a + b)(a - b)Hence, (0.16)² - (0.12)²= (0.16 + 0.12)(0.16 - 0.12)= 0.28 x 0.04 = 0.0112
Fractions and Decimals 0.001 / ? = 0.01 None of these 0.1 0.01 0.001 None of these 0.1 0.01 0.001 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let 0.001 / x = 0.01 Then , x = 0.001 / 0.01 = 0.001 / 0.010= 1 / 10 = 0.1
Fractions and Decimals (.356 x .365 - 2 x .365 x .106 + .106 x .106) / (.632 x .632 + 2 x .632 x .368 +.368 x .368) = ? .625 .0625 6.25 62.5 .625 .0625 6.25 62.5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(.356)² -2 x .356 x .106 + (.106)²] / [(.632)²+2 x .632 x .368 +(.368)²]= (a² -2ab + b²) / (c²+2cd+d²)= (a - b)² / (c + d)²= (.356 -.106)² / (.632 + .368)²= (.25)² = .0625
Fractions and Decimals The rational number for recurring decimal 0.125125.... is: 125/99 125/100 125/999 125/1000 125/99 125/100 125/999 125/1000 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP _0.125125... = 0.125 =125/999
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