Chemical Engineering Thermodynamics Two substances are in equilibrium in a reversible chemical reaction. If the concentration of each substance is doubled, then the value of the equilibrium constant will be Halved Same One fourth of its original value Doubled Halved Same One fourth of its original value Doubled ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics The following heat engine produces power of 100000 kW. The heat engine operates between 800 K and 300 K. It has a thermal efficiency equal to 50% of that of the Carnot engine for the same temperature. The rate at which heat is absorbed from the hot reservoir is 100, 000 kW 160, 000 kW 320, 000 kW 200, 000 kW 100, 000 kW 160, 000 kW 320, 000 kW 200, 000 kW ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Air enters an adiabatic compressor at 300K. The exit temperature for a compression ratio of 3, assuming air to be an ideal gas (Y = Cp/Cv = 7/5) and the process to be reversible, is 300(33/5) 300(35/7) 300(32/7) 300(33/7) 300(33/5) 300(35/7) 300(32/7) 300(33/7) ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics For an isothermal reversible compression of an ideal gas ΔE = ΔH = 0 Only ΔE = 0 Only ΔH =0 DQ = dE ΔE = ΔH = 0 Only ΔE = 0 Only ΔH =0 DQ = dE ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics If heat contents of CH₄, C₂H₄ and C₃H₈ are -17.9, 12.5 and -24.8 kcal/mole respectively, than ΔH for the reaction CH₄(g) + C₂H₄(g) ⇋ C₃H₈(g) will be __________ Kcal. -55.2 55.2 -30.2 -19.4 -55.2 55.2 -30.2 -19.4 ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Which of the following identities can be most easily used to verify steam table data for superheated steam. (∂P/∂T)V = (∂S/∂V)T (∂T/∂V)S = (∂p/∂S)V (∂T/∂P)S = (∂V/∂S)P (∂V/∂T)P = -(∂S/∂P)T (∂P/∂T)V = (∂S/∂V)T (∂T/∂V)S = (∂p/∂S)V (∂T/∂P)S = (∂V/∂S)P (∂V/∂T)P = -(∂S/∂P)T ANSWER DOWNLOAD EXAMIANS APP
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