MGVCL Exam Paper (30-07-2021 Shift 2) Transistors were used in ____ of Computers. First Generation Third Generation Fourth Generation Second Generation First Generation Third Generation Fourth Generation Second Generation ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A sudden, non power frequency change in the steady state condition of voltage or current that is bidirectional in polarity is called as Distortion Oscillatory transients Harmonic Impulsive transient Distortion Oscillatory transients Harmonic Impulsive transient ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Oscillatory transient is the a sudden, non power frequency change in the steady state condition of voltage or current that is bidirectional in polarity.
MGVCL Exam Paper (30-07-2021 Shift 2) In a typical DC micro grid, hybrid storage system is a combination of Lead acid battery and Capacitor None of these Lead acid battery and ultra capacitor / super capacitor Lead acid battery and Lithium ion battery Lead acid battery and Capacitor None of these Lead acid battery and ultra capacitor / super capacitor Lead acid battery and Lithium ion battery ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Hybrid storage system is a combination of microturbines, fuel cells, photovoltaics (PV), Lead acid battery and ultra or super capacitors etc.
MGVCL Exam Paper (30-07-2021 Shift 2) સોહેલ ખાન : મલાયકા અરોર :: સૈફ અલી ખાન : ?? માધુરી દિક્ષિત અમૃતા સિંહ કિરણ ખેર પરવીન બાબી માધુરી દિક્ષિત અમૃતા સિંહ કિરણ ખેર પરવીન બાબી ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A single phase 240 V, 1 kW heater is connected across single phase 240 V, 50 Hz supply through an SCR. For firing angle delay of 90˚, calculate the power absorbed in the heater element. 225 W 275 W 300 W 250 W 225 W 275 W 300 W 250 W ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Resistance of heater, R = V²/PR = 57.6 ohmRMS value of voltage through controlled SCR = (Vm/2π)*(1 + cosα)= 120 VPower absorb by heater = Vrms²/R= 120²/57.6= 250 W
MGVCL Exam Paper (30-07-2021 Shift 2) A delta-connected balanced three-phase load is supplied from a three-phase, 400 V supply. The line current is 20 A and the power taken by the load is 10 kW. Find the power factor. 0.82 0.62 0.52 0.72 0.82 0.62 0.52 0.72 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = 10 kWVL = 400 VIL = 20 A3- phse power, P = √3*VL*IL*cosφcosφ = 10*1000/(√3*400*20)= 0.7216
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