Refrigeration and Air Conditioning The wet bulb temperature at 100% relative humidity is ________ dew point temperature. Lower than Higher than Same as None of these Lower than Higher than Same as None of these ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning A condenser of refrigeration system rejects heat at the rate of 120 kW, while its compressor consumes a power of 30 kW. The coefficient of performance of the system will be 3 4 43834 43833 3 4 43834 43833 ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The formation of frost on cooling coils in a refrigerator Increases heat transfer Improves C.O.P. of the system Reduces power consumption Increases power consumption Increases heat transfer Improves C.O.P. of the system Reduces power consumption Increases power consumption ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The coefficient of performance of Electrolux refrigerator is the ratio of Heat supplied by the gas burner minus the heat absorbed by the evaporator to the heat supplied by the gas burner Heat supplied by the gas burner to the heat absorbed by the evaporator Heat absorbed by the evaporator minus the heat supplied by the gas burner to the heat absorbed by the evaporator Heat absorbed by the evaporator to the heat supplied by the gas burner Heat supplied by the gas burner minus the heat absorbed by the evaporator to the heat supplied by the gas burner Heat supplied by the gas burner to the heat absorbed by the evaporator Heat absorbed by the evaporator minus the heat supplied by the gas burner to the heat absorbed by the evaporator Heat absorbed by the evaporator to the heat supplied by the gas burner ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning In actual air-conditioning applications for R-12 and R-22, and operating at a condenser temperature of 40° C and an evaporator temperature of 5° C, the heat rejection factor is about 5.12 2.15 1.25 1 5.12 2.15 1.25 1 ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The coefficient of performance (C.O.P.) of a refrigerator working as a heat pump is given by O.P)P = ( O.P.)P = ( ( O.P.)P = ( O.P)R - 1 ( ( O.P)P = ( O.P.)R + 2 O.P)R ( O.P.)R + 1 O.P)P = ( O.P.)P = ( ( O.P.)P = ( O.P)R - 1 ( ( O.P)P = ( O.P.)R + 2 O.P)R ( O.P.)R + 1 ANSWER DOWNLOAD EXAMIANS APP
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