Hydraulics and Fluid Mechanics in ME The unit power developed by a turbine is (where P = Power developed by the turbine under a head of water (H). P/ √H P/ H P/ H² P/ H3/2 P/ √H P/ H P/ H² P/ H3/2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A compound pipe of diameter d1, d2 and d3 having lengths l1, l2 and l3 is to be replaced by an equivalent pipe of uniform diameter d and of the same length (l) as that of the compound pipe. The size of the equivalent pipe is given by l/d⁵ = (l₁/d₁⁵) + (l₂/d₂⁵) + (l₃/d₃⁵) l/d³ = (l₁/d₁³) + (l₂/d₂³) + (l₃/d₃³) l/d² = (l₁/d₁²) + (l₂/d₂²) + (l₃/d₃²) l/d⁴ = (l₁/d₁⁴) + (l₂/d₂⁴) + (l₃/d₃⁴) l/d⁵ = (l₁/d₁⁵) + (l₂/d₂⁵) + (l₃/d₃⁵) l/d³ = (l₁/d₁³) + (l₂/d₂³) + (l₃/d₃³) l/d² = (l₁/d₁²) + (l₂/d₂²) + (l₃/d₃²) l/d⁴ = (l₁/d₁⁴) + (l₂/d₂⁴) + (l₃/d₃⁴) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In one dimensional flow, the flow Takes place in straight line Is steady and uniform Takes place in curve Takes place in one direction Takes place in straight line Is steady and uniform Takes place in curve Takes place in one direction ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The units of dynamic or absolute viscosity are newton-sec per meter kg sec/meter metres² per sec newton-sec² per meter newton-sec per meter kg sec/meter metres² per sec newton-sec² per meter ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The flow in a pipe or channel is said to be uniform when Each liquid particle has a definite path The liquid particles at different sections have different velocities The liquid particles at all sections have the same velocities The quantity of liquid flowing per second is constant Each liquid particle has a definite path The liquid particles at different sections have different velocities The liquid particles at all sections have the same velocities The quantity of liquid flowing per second is constant ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H1 - Ha] ANSWER DOWNLOAD EXAMIANS APP
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