Heat and Mass Transfer The transfer of heat by molecular collision is smallest in None of these Gases Liquids Solids None of these Gases Liquids Solids ANSWER DOWNLOAD EXAMIANS APP
Heat and Mass Transfer According to Kirchoff's law, the ratio of emissive power to absorptivity for all bodies is equal to the emissive power of a Grey body Brilliant white polished body Black body Red hot body Grey body Brilliant white polished body Black body Red hot body ANSWER DOWNLOAD EXAMIANS APP
Heat and Mass Transfer A designer chooses the values of fluid flow rates and specific heats in such a manner that the heat capacities of the two fluids are equal. A hot fluid enters the counter flow heat exchanger at 100°C and leaves at 60°C. A cold fluid enters the heat exchanger at 40°C. The mean temperature difference between the two fluids is 66.7°C 20°C 60°C 40°C 66.7°C 20°C 60°C 40°C ANSWER DOWNLOAD EXAMIANS APP
Heat and Mass Transfer Film coefficient is defined as Inside diameter of tube Thermal conductivity Molecular diffusivity of momentum Thermal diffusivity Equivalent thickness of film Film coefficient × Inside diameter Thermal conductivity Thermal conductivity Equivalent thickness of film Specific heat × Viscosity Thermal conductivity Molecular diffusivity of momentum Thermal diffusivity Equivalent thickness of film Film coefficient × Inside diameter Thermal conductivity Thermal conductivity Equivalent thickness of film Specific heat × Viscosity ANSWER DOWNLOAD EXAMIANS APP
Heat and Mass Transfer Fourier's law of heat conduction is (where Q = Amount of heat flow through the body in unit time, A = Surface area of heat flow, taken at right angles to the direction of heat flow, dT = Temperature difference on the two faces of the body, dx = Thickness of the body, through which the heat flows, taken along the direction of heat flow, and k = Thermal conductivity of the body) k. A. (dT/dx) k. (dT/dx) k. A. (dx/dT) k. (dx/dT) k. A. (dT/dx) k. (dT/dx) k. A. (dx/dT) k. (dx/dT) ANSWER DOWNLOAD EXAMIANS APP
Heat and Mass Transfer In heat transfer, conductance equals conductivity (kcal/hr/sq.m/°C/cm) divided by Hr (time) Sq. m (area) K.cal (heat) °C (temperature) Hr (time) Sq. m (area) K.cal (heat) °C (temperature) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS