Hydraulics and Fluid Mechanics in ME The total head of a liquid particle in motion is equal to Pressure head + kinetic head + potential head Pressure head - (kinetic head + potential head) Kinetic head - (pressure head + potential head) Potential head - (pressure head + kinetic head) Pressure head + kinetic head + potential head Pressure head - (kinetic head + potential head) Kinetic head - (pressure head + potential head) Potential head - (pressure head + kinetic head) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A turbine is required to develop 1500 kW at 300 r.p.m. under a head of 150 m. Which of the following turbine should be used? Kaplan turbine Francis turbine Pelton wheel with one nozzle Pelton wheel with two or more nozzles Kaplan turbine Francis turbine Pelton wheel with one nozzle Pelton wheel with two or more nozzles ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A rectangular block 2 m long, 1 m wide and 1 m deep floats in water, the depth of immersion being 0.5 m. If water weighs 10 kN/m3, then the weight of the block is 5kN lOkN 15 kN 20 kN 5kN lOkN 15 kN 20 kN ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The process of diffusion of one liquid into the other through a semi-permeable membrane is called viscosity osmosis cohesion surface tension viscosity osmosis cohesion surface tension ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The atmospheric pressure with rise in altitude decreases first slowly and then steeply linearly unpredictable first steeply and then gradually first slowly and then steeply linearly unpredictable first steeply and then gradually ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) ANSWER DOWNLOAD EXAMIANS APP
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