Waste Water Engineering The suitable cross-section of sewers to carry combined flow, is Horse shoe shaped Circular Rectangular Egg shaped Horse shoe shaped Circular Rectangular Egg shaped ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering Nitrogen cycle of sewage, is Formation of nitrates-formation of nitrites-liberation of nitrates-liberation of nitrates Liberation of nitrogen-formation of nitrates-formation of nitrites-liberation of ammonia Liberation of nitrogen-liberation of ammonia-formation of nitrites- formation of nitrates Liberation of ammonia-formation of nitrites-formation of nitrates-liberation of nitrogen Formation of nitrates-formation of nitrites-liberation of nitrates-liberation of nitrates Liberation of nitrogen-formation of nitrates-formation of nitrites-liberation of ammonia Liberation of nitrogen-liberation of ammonia-formation of nitrites- formation of nitrates Liberation of ammonia-formation of nitrites-formation of nitrates-liberation of nitrogen ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The normal values of over flow rates for sedimentation tanks using coagulant, ranges between 80,000 to 100,000 litres/sqm/day 50,000 to 60,000 litres/sqm/day 25,000 to 35,000 litres/sqm/day 40,000 to 50,000 litres/sqm/day 80,000 to 100,000 litres/sqm/day 50,000 to 60,000 litres/sqm/day 25,000 to 35,000 litres/sqm/day 40,000 to 50,000 litres/sqm/day ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The gas evolved in sewers is Hydrogen sulphide All of these Methane Carbondioxide Hydrogen sulphide All of these Methane Carbondioxide ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The formula V = (1/n) r2/3 Manning’s formula Bazin’s formula Kutter’s formula Chezy’s formula Manning’s formula Bazin’s formula Kutter’s formula Chezy’s formula ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The settling velocity of a spherical particle of diameter less than 0.1 mm as per Stock’s law, is Vs = 218 (Gs – Gw)d² [(3T + 70)/100] Vs = 218 (Gs – Gw)d [(3T + 70)/100] Vs = 418 (Gs – Gw)d² [(3T + 70)/100] Vs = 418 (Gs – Gw) d [(3T + 70)/100] Vs = 218 (Gs – Gw)d² [(3T + 70)/100] Vs = 218 (Gs – Gw)d [(3T + 70)/100] Vs = 418 (Gs – Gw)d² [(3T + 70)/100] Vs = 418 (Gs – Gw) d [(3T + 70)/100] ANSWER DOWNLOAD EXAMIANS APP
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