Hydraulics and Fluid Mechanics in ME The stress-strain relation of the newtoneon fluid is parabolic hyperbolic linear inverse type parabolic hyperbolic linear inverse type ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The point in the immersed body through which the resultant pressure of the liquid may be taken to act is known as center of pressure center of buoyancy metacentre center of gravity center of pressure center of buoyancy metacentre center of gravity ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a wholly drowned orifice is given by (where H1 = Height of water (on the upstream side) above the top of the orifice, H2 = Height of water (on the downstream side) above the bottom of the orifice, and H = Difference between two water levels on either side of the orifice) Q = Cd × bH2 × √(2gh) Q = Cd × bH₁ × √(2gh) Q = Cd × b (H2 - H1) × √(2gh) Q = Cd × bH × √(2gh) Q = Cd × bH2 × √(2gh) Q = Cd × bH₁ × √(2gh) Q = Cd × b (H2 - H1) × √(2gh) Q = Cd × bH × √(2gh) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A hydraulic intensifier normally consists of A cylinder, a piston, storage tank and control valve A cylinder and a ram Two coaxial rams and two cylinders Two cylinders, two rams and a storage device A cylinder, a piston, storage tank and control valve A cylinder and a ram Two coaxial rams and two cylinders Two cylinders, two rams and a storage device ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME An impulse turbine is used for High discharge Low head of water Medium head of water High head of water High discharge Low head of water Medium head of water High head of water ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A compound pipe of diameter d1, d2 and d3 having lengths l1, l2 and l3 is to be replaced by an equivalent pipe of uniform diameter d and of the same length (l) as that of the compound pipe. The size of the equivalent pipe is given by l/d⁵ = (l₁/d₁⁵) + (l₂/d₂⁵) + (l₃/d₃⁵) l/d² = (l₁/d₁²) + (l₂/d₂²) + (l₃/d₃²) l/d⁴ = (l₁/d₁⁴) + (l₂/d₂⁴) + (l₃/d₃⁴) l/d³ = (l₁/d₁³) + (l₂/d₂³) + (l₃/d₃³) l/d⁵ = (l₁/d₁⁵) + (l₂/d₂⁵) + (l₃/d₃⁵) l/d² = (l₁/d₁²) + (l₂/d₂²) + (l₃/d₃²) l/d⁴ = (l₁/d₁⁴) + (l₂/d₂⁴) + (l₃/d₃⁴) l/d³ = (l₁/d₁³) + (l₂/d₂³) + (l₃/d₃³) ANSWER DOWNLOAD EXAMIANS APP
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