DNA Structure and Replication The size of a linear DNA fragment in a gel can be estimated by comparison with a molecular weight standard such as Hind III digested phage lambda the time it takes the gel to run fluorescence in UV light the sedimentation coefficient comparison with a molecular weight standard such as Hind III digested phage lambda the time it takes the gel to run fluorescence in UV light the sedimentation coefficient ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication In DNA double helix, the two DNA chains are held together by None of these covalent bonds between the pair of bases ionic bonds between the pair of bases hydrogen bonds between the pair of bases None of these covalent bonds between the pair of bases ionic bonds between the pair of bases hydrogen bonds between the pair of bases ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Without telomerase, what would happen to the ends of chromosomes after each round of replication? Chromosomes would get longer Chromosomes would become progressively shorter Nothing would happen None of these Chromosomes would get longer Chromosomes would become progressively shorter Nothing would happen None of these ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication The overall conclusion of the Hershey-Chase experiment was that the ratio of Adenine to thymine was always the same phage DNA was similar to bacterial DNA DNA was responsible for heredity proteins and DNA were responsible for heredity the ratio of Adenine to thymine was always the same phage DNA was similar to bacterial DNA DNA was responsible for heredity proteins and DNA were responsible for heredity ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Enzyme, responsible for proofreading base pairing is DNA polymerase Primase Telomerase DNA ligase DNA polymerase Primase Telomerase DNA ligase ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Which of the following is used to determine the appropriate stringency (Wallace rule)? Tm = 2 x (No.of G:C base pair) + 4 x (No.of A:T base pair) Tm = 4 x (No.of A:T base pair) + 2 x (No.of G:C base pair) Tm = 4 x (No.of G:C base pair) + 2 x (No.of A:T base pair) Tm = 69.3° + 0.41 (%)G+C -650/1 Tm = 2 x (No.of G:C base pair) + 4 x (No.of A:T base pair) Tm = 4 x (No.of A:T base pair) + 2 x (No.of G:C base pair) Tm = 4 x (No.of G:C base pair) + 2 x (No.of A:T base pair) Tm = 69.3° + 0.41 (%)G+C -650/1 ANSWER DOWNLOAD EXAMIANS APP
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