Machine Design The shock resistance of steel is increased by adding Chromium Nickel and chromium Nickel Cobalt and molybdenum Chromium Nickel and chromium Nickel Cobalt and molybdenum ANSWER DOWNLOAD EXAMIANS APP
Machine Design Which of the following has threads at both ends? Tap bolt Bolt Stud None of these Tap bolt Bolt Stud None of these ANSWER DOWNLOAD EXAMIANS APP
Machine Design In skew bevel gearing, the axes of shafts are Non-intersecting and nonparallel and the teeth are curved None of these Intersecting and the teeth are curved Non-intersecting and non-parallel and the teeth are straight Non-intersecting and nonparallel and the teeth are curved None of these Intersecting and the teeth are curved Non-intersecting and non-parallel and the teeth are straight ANSWER DOWNLOAD EXAMIANS APP
Machine Design The anti-friction bearings Have high initial cost All of these Have low starting and low running friction at moderate speeds Can carry both radial and thrust loads Have high initial cost All of these Have low starting and low running friction at moderate speeds Can carry both radial and thrust loads ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to I.B.R., when the thickness of boiler shell (t) is greater than 8 mm, then the diameter of rivet hole (d) is obtained by None of these Equating shearing resistance to the crushing resistance of the rivets Equating tearing resistance of the plate to the shearing resistance of the rivets Equating tearing resistance of the plate to the crushing resistance of the rivets None of these Equating shearing resistance to the crushing resistance of the rivets Equating tearing resistance of the plate to the shearing resistance of the rivets Equating tearing resistance of the plate to the crushing resistance of the rivets ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given byWhere m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of frictiona = angle of wrap (radians) (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = e–ᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = e–ᶠα P1 / P2 = eᶠα ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS