Machine Design The shock resistance of steel is increased by adding Nickel and chromium Chromium Cobalt and molybdenum Nickel Nickel and chromium Chromium Cobalt and molybdenum Nickel ANSWER DOWNLOAD EXAMIANS APP
Machine Design For circumferential joint in boilers, the type of joint used is Lap joint with one ring overlapping the other Butt joint with single cover plate Butt joint with double cover plate Any one of the above Lap joint with one ring overlapping the other Butt joint with single cover plate Butt joint with double cover plate Any one of the above ANSWER DOWNLOAD EXAMIANS APP
Machine Design Tensile strength of a mild steel specimen can be roughly predicted from following hardness test None of these Brinell Rockwell Vickers None of these Brinell Rockwell Vickers ANSWER DOWNLOAD EXAMIANS APP
Machine Design In a hydrodynamic lubricated bearing There is no lubricant between the journal and the bearing There is a thick film of lubricant between the journal and the bearing There is a thin film of lubricant between the journal and the bearing The lubricant is forced between the journal and the bearing, by external pressure There is no lubricant between the journal and the bearing There is a thick film of lubricant between the journal and the bearing There is a thin film of lubricant between the journal and the bearing The lubricant is forced between the journal and the bearing, by external pressure ANSWER DOWNLOAD EXAMIANS APP
Machine Design In the assembly of pulley, key and shaft Key is made the weakest Key is made the strongest All the three are designed for equal strength Pulley is made the weakest Key is made the weakest Key is made the strongest All the three are designed for equal strength Pulley is made the weakest ANSWER DOWNLOAD EXAMIANS APP
Machine Design In a band and block brake, the ratio of tensions on the tight and slack sides of band is given by (where μ = Coefficient of friction between the blocks and the drum, θ = Semi-angle of each block subtending at the centre of drum, and n = Number of blocks) T₁/T₂ = (μθ)n T₁/T₂ = μθ × n T₁/T₂ = [(1 - μ tanθ)/ (1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/ (1 - μ tanθ)]n T₁/T₂ = (μθ)n T₁/T₂ = μθ × n T₁/T₂ = [(1 - μ tanθ)/ (1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/ (1 - μ tanθ)]n ANSWER DOWNLOAD EXAMIANS APP
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