Steam Boilers, Engines, Nozzles and Turbines The rate of discharge through the nozzle ___ when the exit pressure is gradually reduced. Decreases Remains same Increases None of the listed here Decreases Remains same Increases None of the listed here ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines Adiabatic process is Constant temperature process Essentially an isentropic process Reversible process Non-heat transfer process Constant temperature process Essentially an isentropic process Reversible process Non-heat transfer process ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines Spontaneous combustion is a phenomenon in which All the fuel burns instantaneously producing high energy release Coal bursts into flame without any external ignition source but by itself due to gradual increase in temperature as a result of heat released by combination of oxygen with coal Explosion in furnace Fuel burns with less air All the fuel burns instantaneously producing high energy release Coal bursts into flame without any external ignition source but by itself due to gradual increase in temperature as a result of heat released by combination of oxygen with coal Explosion in furnace Fuel burns with less air ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines A safety valve mainly used with locomotive and marine boilers is Dead weight safety valve Spring loaded safety valve Lever safety valve High steam and low water safety valve Dead weight safety valve Spring loaded safety valve Lever safety valve High steam and low water safety valve ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines For the same diameter and thickness of tube, a water tube boiler has ________ heating surface as compared to fire tube boiler. None of these More Less Equal None of these More Less Equal ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines Willian’s line follows the law (where b = A constant representing the shape of the Willian’s line, a = Another constant i.e. no load consumption per hour, I.P. = Indicated power, and m = Steam consumption per hour) I.P. = b × m + a m = (b/I.P.) - a I.P. = a × m + b m = a + b × I.P. I.P. = b × m + a m = (b/I.P.) - a I.P. = a × m + b m = a + b × I.P. ANSWER DOWNLOAD EXAMIANS APP
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