Hydraulics and Fluid Mechanics in ME The power transmitted through a pipe is (where w = Specific weight in N/m3, and Q = Discharge in m3/s) w × Q × hf w × Q (H - hf) w × Q (H + hf) w × Q × H w × Q × hf w × Q (H - hf) w × Q (H + hf) w × Q × H ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME To avoid an interruption in the flow of a syphon, an air vessel is provided at the outlet ay nay point between inlet and outlet at the inlet at the summit at the outlet ay nay point between inlet and outlet at the inlet at the summit ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In case of flow through parallel pipes, The total discharge is equal to the sum of discharges in the various pipes The total head loss is the sum of head losses in the various pipes Both (A) and (B) The head loss for all the pipes is same The total discharge is equal to the sum of discharges in the various pipes The total head loss is the sum of head losses in the various pipes Both (A) and (B) The head loss for all the pipes is same ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The viscosity of water at 20°C is One centistoke One stoke One poise One centipoise One centistoke One stoke One poise One centipoise ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME For similarity, in addition to models being geometrically similar to prototype, the following in both cases should also be equal ratio of inertial force to force due to surface tension all the four ratios of inertial force to force due to viscosity, gravitation, surface tension, and elasticity ratio of inertial force to force due to gravitation ratio of inertial force to force due to viscosity ratio of inertial force to force due to surface tension all the four ratios of inertial force to force due to viscosity, gravitation, surface tension, and elasticity ratio of inertial force to force due to gravitation ratio of inertial force to force due to viscosity ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Francis formula, the discharge over a rectangular weir is (where n = Number of end contractions) (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 ANSWER DOWNLOAD EXAMIANS APP
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