Hydraulics and Fluid Mechanics in ME The optimum value of vane exit angle for a centrifugal pump impeller is 50-60° 30-40° 20-25° 10-15° 50-60° 30-40° 20-25° 10-15° ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME If a pump is handling water and is discharging a certain flow Q at a constant total dynamic head requiring a definite B.H.P., the same pump when handling a liquid of specific gravity 0.75 and viscosity nearly same as of water , the horse power required will be 1.5 B.H.P Same 0.75 B.H.P H.P./0.75 1.5 B.H.P Same 0.75 B.H.P H.P./0.75 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A turbine develops 10000 kW under a head of 25 meters at 135 r.p.m. Its specific speed is 215.5 r.p.m. 275.4 r.p.m 241.5 r.p.m. 175.4 r.p.m. 215.5 r.p.m. 275.4 r.p.m 241.5 r.p.m. 175.4 r.p.m. ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Coefficient of contraction is the ratio of Actual velocity of jet at vena contracta to the theoretical velocity Loss of head in the orifice to the head of water available at the exit of the orifice Loss of head in the orifice to the head of water available at the exit of the orifice Area of jet at vena-contracta to the area of orifice Actual velocity of jet at vena contracta to the theoretical velocity Loss of head in the orifice to the head of water available at the exit of the orifice Loss of head in the orifice to the head of water available at the exit of the orifice Area of jet at vena-contracta to the area of orifice ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The atmospheric pressure with rise in altitude decreases first slowly and then steeply first steeply and then gradually unpredictable linearly first slowly and then steeply first steeply and then gradually unpredictable linearly ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The error in discharge (dQ/Q) to the error in measurement of head (dH/H) over a triangular notch is given by dQ/Q = 2 × (dH/H) dQ/Q = 3/2 × (dH/H) dQ/Q = 3 × (dH/H) dQ/Q = 5/2 × (dH/H) dQ/Q = 2 × (dH/H) dQ/Q = 3/2 × (dH/H) dQ/Q = 3 × (dH/H) dQ/Q = 5/2 × (dH/H) ANSWER DOWNLOAD EXAMIANS APP