Engineering Thermodynamics The main cause for the irreversibility is Unrestricted expansion Heat transfer with a finite temperature difference All of these Mechanical and fluid friction Unrestricted expansion Heat transfer with a finite temperature difference All of these Mechanical and fluid friction ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The ideal efficiency of a Brayton cycle without regeneration, with increase in pressure ratio will Remain unchanged Increase/decrease depending on application Increase Decrease Remain unchanged Increase/decrease depending on application Increase Decrease ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Otto cycle consists of One constant pressure, one constant volume and two isentropic processes Two constant volume and two isentropic processes Two constant volume and two isothermal processes Two constant pressure and two isentropic processes One constant pressure, one constant volume and two isentropic processes Two constant volume and two isentropic processes Two constant volume and two isothermal processes Two constant pressure and two isentropic processes ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The area under the temperature-entropy curve (T – s curve) of any thermodynamic process represents Heat rejected Heat absorbed None of the listed here Either heat absorbed or heat rejected Heat rejected Heat absorbed None of the listed here Either heat absorbed or heat rejected ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics For reversible adiabatic process, change in entropy is Negative Minimum Zero Maximum Negative Minimum Zero Maximum ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The value of the product of molecular weight and the gas characteristic constant for all the gases in S.I. units is 29.27 J/kmol °K 83.14 J/kmol °K 735 J/kmol °K 848 J/kmol °K 29.27 J/kmol °K 83.14 J/kmol °K 735 J/kmol °K 848 J/kmol °K ANSWER DOWNLOAD EXAMIANS APP
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