Area Problems The length of minute hand of a wall clock is 7 cms. The area swept by minute hand in 30 minutes is? 210 sq. cm 147 sq. cm 154 sq. cm 77 sq. cm 210 sq. cm 147 sq. cm 154 sq. cm 77 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Angle swept in 30 min= 180° Area swept = [(22/7) x 7 x 7] x [180°/360°] cm2 = 77 cm2
Area Problems The length of a rectangular field is 100 m and its breadth is 40 m. What will be the area of the field? (4 x 102) sq m (4 x 103) sq m (4 x 104) sq m (4 x 10) sq m (4 x 102) sq m (4 x 103) sq m (4 x 104) sq m (4 x 10) sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 100 x 40 = 4000 sq m= 4 x 103 sq m
Area Problems The ratio of the area of a square to that of the square drawn on its diagonal is 1:2 4:1 3:1 2;3 1:2 4:1 3:1 2;3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP atio = a 2 2 a 2
Area Problems The ratio between the length and breadth of a rectangular field is 5:4. If the breadth is 20 meters less than the length, the perimeters of the field is? 260 m none of these 360 m 280 m 260 m none of these 360 m 280 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length of rectangular field = 5y,so width = 4y.From question5y - 4y = 20m? x = 20m ? Length = (5 x 20)m = 100 mBreadth = (4 x 20) m = 80 m ? Perimeter = 2 (100 + 80 ) m = 360 m
Area Problems The diagonals of two squares are in the ratio of 3 : 2. Find the ratio of their areas. 9 : 7 9 : 5 9 : 4 9 : 2 9 : 7 9 : 5 9 : 4 9 : 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the diagonals of the squares be 3x and 2x.? Ratio of their areas = [(1/2) (3x2)] / [(1/2) (2x2)] = 9/4
Area Problems The area of an equilateral triangle is ? 243 /4 sq cm. Find the length of its side. 3 cm ?3 cm 3?3 cm 9 cm 3 cm ?3 cm 3?3 cm 9 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the question,area = ?3a2/4 = ?243 /4? a2 = ?81 x 3/?3 ? a = ?9 = 3 cm
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