Area Problems The length of minute hand of a wall clock is 7 cms. The area swept by minute hand in 30 minutes is? 210 sq. cm 77 sq. cm 154 sq. cm 147 sq. cm 210 sq. cm 77 sq. cm 154 sq. cm 147 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Angle swept in 30 min= 180° Area swept = [(22/7) x 7 x 7] x [180°/360°] cm2 = 77 cm2
Area Problems The length and breadth of a playground are 36 m and 21 m respectively. Flagstaffs are required to be fixed on all along the boundary at a distance of 3 m apart. The number of flagstaffs will be? 40 37 38 39 40 37 38 39 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Perimeter = 2 x (36 + 21 ) m = 144 m ? Number of flagstaffs = 144 / 3 = 38
Area Problems The ratio of the radii of two circle is 1:3 the radio of their areas is? 1:9 1:6 1:3 None of these 1:9 1:6 1:3 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Radio of areas = area of first circle : area of 2nd circle= ?r2 / ?(3r)2= ?r2/ 9 ?r2= 1/9 = 1: 9
Area Problems The area of a trapezium is 384 sq.cm 2. If its parallel sides are in ratio 3 : 5 and the perpendicular distance between them be 12 cm, The smaller of parallel sides is? 24 cm 36 cm 20 cm 30 cm 24 cm 36 cm 20 cm 30 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the sides of trapezium be 5k and 3k, respectively According to the question, (1/2) x [(5k + 3k) x 12] = 384? 8k = (384 x 2)/12 = 64 ? k = 64/8 = 8 cmLength of smaller of the parallel sides = 8 x 3 = 24 cm
Area Problems The ratio of the area of a square to that of the square drawn on its diagonal is 2;3 1:2 4:1 3:1 2;3 1:2 4:1 3:1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP atio = a 2 2 a 2
Area Problems The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres? Data inadequate None of these 40 120 Data inadequate None of these 40 120 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m
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