Surveying The latitude of a place was obtained by subtracting the zenith distance of a star from its declination, the observed star was between Equator and zenith Zenith and pole Pole and horizon Horizon and equator Equator and zenith Zenith and pole Pole and horizon Horizon and equator ANSWER DOWNLOAD EXAMIANS APP
Surveying To avoid large centering error with very short legs, observations are generally made All listed here To a target fixed on theodolite tripod on which theodolite may be fitted easily By using optical system for centering the theodolite To chain pins All listed here To a target fixed on theodolite tripod on which theodolite may be fitted easily By using optical system for centering the theodolite To chain pins ANSWER DOWNLOAD EXAMIANS APP
Surveying The distance between the projection centre and the photograph, is called Principal distance Principal line Focal length Isocentric distance Principal distance Principal line Focal length Isocentric distance ANSWER DOWNLOAD EXAMIANS APP
Surveying Places having same latitude All listed here Lie on the parallel of the latitude Are equidistant from both the poles Are equidistant from the nearer pole All listed here Lie on the parallel of the latitude Are equidistant from both the poles Are equidistant from the nearer pole ANSWER DOWNLOAD EXAMIANS APP
Surveying The line of collimation method of reduction of levels, does not provide a check on Back sights Fore sights Intermediate sights Reduced levels Back sights Fore sights Intermediate sights Reduced levels ANSWER DOWNLOAD EXAMIANS APP
Surveying If ‘δ’ is the declination of the star and ‘φ’ is the latitude of the observer then the hour angle of the star at elongation is given by cos H = tan φ . cot δ None of these tan H = tan φ . cot δ sin H = tan φ . cot δ cos H = tan φ . cot δ None of these tan H = tan φ . cot δ sin H = tan φ . cot δ ANSWER DOWNLOAD EXAMIANS APP
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