Area Problems The inner circumference of a circular race track, 14 m wide is 440 m . Then the radius of the outer circle is? 77 m 84 m 70 m 56 m 77 m 84 m 70 m 56 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference of a circular = 2?r? 2 x (22 / 7) x r = 440? r = [440 x (7/22) x (1/2)] = 70 m? Radius of outer circle = (70 + 14) m = 84 m
Area Problems Find the area of a rectangle having 15m length and 8m breadth. 111 sq m 120 sq m 125 sq m 115 sq m 111 sq m 120 sq m 125 sq m 115 sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 15 x 8 = 120 sq m
Area Problems The length of a plot is four times its breath. A playground measuring 1200 square meters occupies one third of the total area of a plot . what is the length of the plot in meters? 30 60 None of these 20 30 60 None of these 20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the plot = (3 x 1200) m2= 3600 m2Let breadth = y metersThen Length = 4y meters,Now area = 4y x y = 3600 m2? y2 = 900 m2? y = 30 m? Length of plot = 4y m= (4 x 30) m=120 m
Area Problems The Number of rounds that a wheel of diameter 7/11 m will make in going 4 km, is? 1700 2000 1500 1000 1700 2000 1500 1000 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Number of round = total distance / circumference of wheel.= (4 x 1000) / ?d= (4 x 1000) / ( 22/7 x 7/11) = 2000
Area Problems The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field? 30 m 50 m 20 m 40 m 30 m 50 m 20 m 40 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x meters. Then, Length = 115x / 100 meters Given that, X × (115X / 100) = 460 => X = 20
Area Problems A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is rs.58 rs.358 rs.258 rs.158 rs.58 rs.358 rs.258 rs.158 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x (75/100) = Rs. 258
EXAMIANS