Control Systems The impulse response of an initally relaxed linear system is e-2tu(t). To produce a response of te-2tu(t), the input must be equal to 2e-tu(t). e-tu(t). e-2tu(t). (0.5)e-2tu(t). 2e-tu(t). e-tu(t). e-2tu(t). (0.5)e-2tu(t). ANSWER DOWNLOAD EXAMIANS APP
Control Systems The transfer function of a system is given as below, if a = 0.1, then the steady state error to unity ramp input will be 0.16. 0.25. 0.49. 0.35. 0.16. 0.25. 0.49. 0.35. ANSWER DOWNLOAD EXAMIANS APP
Control Systems In polar plots if the critical point '-1+j0' is enclosed then the system is -------- critical stable unstable marginally stable stable critical stable unstable marginally stable stable ANSWER DOWNLOAD EXAMIANS APP
Control Systems For a transfer function H (s) = P(s) / Q(s), where P (s) and Q (s) are polynomials in s. Then the degree of P (s) and Q (s) are same. the degree of P (s) is always greater than the degree of Q (s). maximum degree of P (s) and Q (s) differ at most by one. degree of P (s) is independent of degree of Q (s). the degree of P (s) and Q (s) are same. the degree of P (s) is always greater than the degree of Q (s). maximum degree of P (s) and Q (s) differ at most by one. degree of P (s) is independent of degree of Q (s). ANSWER DOWNLOAD EXAMIANS APP
Control Systems A second order control system is defined by the following equation: 4 d²c(t)/dt² + 8 dc(t)/dt + 16 c(t) = 16 u(t) The damping ratio and natural frequency for this system are respectively 0.25 and 2 rad/s 0.25 and 4 rad/s 0.50 and 2 rad/s 0.50 and 4 rad/s 0.25 and 2 rad/s 0.25 and 4 rad/s 0.50 and 2 rad/s 0.50 and 4 rad/s ANSWER DOWNLOAD EXAMIANS APP
Control Systems Find the angles of asymptotes of the open loop transfer function G(s) = k(s + 1)/((s(s+2)(s+4)? 60°,240° 0°, 180° 90°,270° 90°,180° 60°,240° 0°, 180° 90°,270° 90°,180° ANSWER DOWNLOAD EXAMIANS APP
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