Refrigeration and Air Conditioning The freezing point of R-12 is -107.7°C -95.2°C -135.8°C -86.6°C -107.7°C -95.2°C -135.8°C -86.6°C ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning Ammonia absorption refrigeration cycle requires Nearly same work input as for vapour compression cycle Zero work input Maximum work input Very little work input Nearly same work input as for vapour compression cycle Zero work input Maximum work input Very little work input ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The coefficient of performance (C.O.P.) of a refrigerator working as a heat pump is given by O.P.)R + 2 O.P.)R + 1 O.P)R - 1 ( O.P.)P = ( ( O.P)P = ( O.P.)P = ( O.P)R ( ( O.P)P = ( O.P.)R + 2 O.P.)R + 1 O.P)R - 1 ( O.P.)P = ( ( O.P)P = ( O.P.)P = ( O.P)R ( ( O.P)P = ( ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning Pressure of water vapour is given by 0.622 Pv/ (Pb - Pv) None of these [Pv (Pb - Pd)]/ [Pd (Pb - Pv)] μ/[1 - (1 - μ) (Ps/Pb)] 0.622 Pv/ (Pb - Pv) None of these [Pv (Pb - Pd)]/ [Pd (Pb - Pv)] μ/[1 - (1 - μ) (Ps/Pb)] ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning In vapour compression cycle using NH₃ as refrigerant, initial charge is filled at Low pressure side near receiver Suction of compressor Delivery of compressor High pressure side close to receiver Low pressure side near receiver Suction of compressor Delivery of compressor High pressure side close to receiver ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The formation of frost on cooling coils in a refrigerator Improves C.O.P. of the system Increases heat transfer Reduces power consumption Increases power consumption Improves C.O.P. of the system Increases heat transfer Reduces power consumption Increases power consumption ANSWER DOWNLOAD EXAMIANS APP
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