Theory of Machine The example of completely constrained motion is a All of these Motion of a shaft with collars at each end in a circular hole Motion of a piston in the cylinder of a steam engine Motion of a square bar in a square hole All of these Motion of a shaft with collars at each end in a circular hole Motion of a piston in the cylinder of a steam engine Motion of a square bar in a square hole ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A point B on a rigid link AB moves with respect to A with angular velocity ω rad/s. The radial component of the acceleration of B with respect to A, is (where vBA = Linear velocity of B with respect to A) v²BA v²BA /AB vBA /AB vBA × AB v²BA v²BA /AB vBA /AB vBA × AB ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a mechanism, the fixed instantaneous centers are those centers which Remain in the same place for all configurations of the mechanism Moves as the mechanism moves, but joints are of permanent nature Vary with the configuration of the mechanism None of the listed here Remain in the same place for all configurations of the mechanism Moves as the mechanism moves, but joints are of permanent nature Vary with the configuration of the mechanism None of the listed here ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A circular bar moving in a round hole is an example of Partially constrained motion Completely constrained motion Successfully constrained motion Incompletely constrained motion Partially constrained motion Completely constrained motion Successfully constrained motion Incompletely constrained motion ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frequency of oscillation at compared to earth will be 2.44 times less 2.44 times more 6 times more 6 times less 2.44 times less 2.44 times more 6 times more 6 times less ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a band and block brake, the ratio of tensions on tight side and slack side of the band is (where μ = Coefficient of friction between the blocks and the drum, θ = Semi-angle of each block subtending at the center of drum, and n = Number of blocks) T₁/T₂ = (μ θ)n T₁/T₂ = μ. θ. n T₁/T₂ = [(1 - μ tanθ)/(1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/(1 - μ tanθ)]n T₁/T₂ = (μ θ)n T₁/T₂ = μ. θ. n T₁/T₂ = [(1 - μ tanθ)/(1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/(1 - μ tanθ)]n ANSWER DOWNLOAD EXAMIANS APP
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