Process Equipment and Plant Design The equivalent diameter for fluid flow through a channel of constant non-circular cross section of area 'A' is given by (where, P = perimeter of the channel in contact with the fluid) 4 A/P A/P 4 P/A √A 4 A/P A/P 4 P/A √A ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Normal screwed fittings are used for pipes upto a diameter of __________ inches. 3 1.5 5 7 3 1.5 5 7 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design The type of stress developed in a metallic bar on subjecting it to a change in temperature without allowing it to be deformed is __________ stress. Compressive Tensile Thermal Shear Compressive Tensile Thermal Shear ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Reflux ratio variation in a distillation column is between Zero and one None of these Minimum and infinity Zero and infinity Zero and one None of these Minimum and infinity Zero and infinity ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Large process vessels operating under extreme temperature and pressure conditions are normally clad/ lined with materials like stainless steel, aluminium, nickel & its alloys, copper & its alloys and titanium. The cladding thickness is generally about __________ percent of the total thickness. 1 to 5 10 to 20 40 to 50 30 to 40 1 to 5 10 to 20 40 to 50 30 to 40 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design For turbulent flow (NRe > 2100) of low viscosity fluid (μ > 20cp) in steel pipes, the optimum inside pipe diameter is given by(where, Q = fluid flow rate, ft³/sec.ρ = fluid density, lb/ft³ μ = fluid viscosity, centipoise Di = optimum inside pipe diameter, inches) Di, opt = 3.9 Q0.45 ρ0.13 Di, opt = 3.9 Q0.45 . μ0.95 Di, opt = 4.7 Q0.36 . μ3.2ρ0.13 Di, opt = 3 Q0.36 . μ0.88 Di, opt = 3.9 Q0.45 ρ0.13 Di, opt = 3.9 Q0.45 . μ0.95 Di, opt = 4.7 Q0.36 . μ3.2ρ0.13 Di, opt = 3 Q0.36 . μ0.88 ANSWER DOWNLOAD EXAMIANS APP
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