Hydraulics and Fluid Mechanics in ME The discharge through a siphon spillway is Cd × a × √(2gH) Cd × a × √(2g) × H5/2 Cd × a × √(2g) × H3/2 Cd × a × √(2g) × H2 Cd × a × √(2gH) Cd × a × √(2g) × H5/2 Cd × a × √(2g) × H3/2 Cd × a × √(2g) × H2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In a forced vortex, the velocity of flow everywhere within the fluid is zero maximum minimum non-zero finite zero maximum minimum non-zero finite ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The overall efficiency of a reaction turbine is the ratio of Work-done on the wheel to the energy (or head of water) actually supplied to the turbine None of these Power produced by the turbine to the energy actually supplied by the turbine Actual work available at the turbine to the energy imparted to the wheel Work-done on the wheel to the energy (or head of water) actually supplied to the turbine None of these Power produced by the turbine to the energy actually supplied by the turbine Actual work available at the turbine to the energy imparted to the wheel ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A moving fluid mass may be brought to a static equilibrium position, by applying an imaginary inertia force of the same magnitude as that of the accelerating force but in the opposite direction. This statement is called D-Alembert’s principle Pascal’s law Archimedes’s principle None of these D-Alembert’s principle Pascal’s law Archimedes’s principle None of these ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The speed of sound in a ideal gas varies directly as its modulus of elasticity density temperature absolute temperature modulus of elasticity density temperature absolute temperature ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be 2A × √H₁/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) ANSWER DOWNLOAD EXAMIANS APP