Heat and Mass Transfer The critical temperature is the temperature Below which a gas does not obey gas laws Above which a gas may explode Above which a gas will never liquefied Below which a gas is always liquefied Below which a gas does not obey gas laws Above which a gas may explode Above which a gas will never liquefied Below which a gas is always liquefied ANSWER DOWNLOAD EXAMIANS APP
Heat and Mass Transfer The value of Prandtl number for air is about 0.3 1.7 0.1 0.7 0.3 1.7 0.1 0.7 ANSWER DOWNLOAD EXAMIANS APP
Heat and Mass Transfer The time constant of a thermocouple is Determined by the time taken to reach 100°C from 0°C The time taken to attain 63.2% of the value of initial temperature difference The time taken to attain the final temperature to be measured The time taken to attain 50% of the value of initial temperature difference Determined by the time taken to reach 100°C from 0°C The time taken to attain 63.2% of the value of initial temperature difference The time taken to attain the final temperature to be measured The time taken to attain 50% of the value of initial temperature difference ANSWER DOWNLOAD EXAMIANS APP
Heat and Mass Transfer According to Stefan's law, the total radiation from a black body per second per unit area is proportional to T5 Absolute temperature T T2 T5 Absolute temperature T T2 ANSWER DOWNLOAD EXAMIANS APP
Heat and Mass Transfer According to Prevost theory of heat exchange Heat transfer by radiation requires no medium Heat transfer in most of the cases takes place by combination of conduction, convection and radiation All bodies above absolute zero emit radiation It is impossible to transfer heat from low temperature source to t high temperature source Heat transfer by radiation requires no medium Heat transfer in most of the cases takes place by combination of conduction, convection and radiation All bodies above absolute zero emit radiation It is impossible to transfer heat from low temperature source to t high temperature source ANSWER DOWNLOAD EXAMIANS APP
Heat and Mass Transfer Thermal diffusivity of a substance is given by (where h = Thermal diffusivity, ρ = Density of substance, S = Specific heat, and k = Thermal conductivity) h = k/ ρS h = S/ρk h = ρS/k h = kρ/S h = k/ ρS h = S/ρk h = ρS/k h = kρ/S ANSWER DOWNLOAD EXAMIANS APP
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