The cost of type - I rice is Rs. 15 per kg and type - II is Rs. 20 per kg. If both type - I and type - II are mixed in the ratio of 2 : 3, then find the price per kg of the mixed variety.

Alligation or Mixture problems
The cost of type - I rice is Rs. 15 per kg and type - II is Rs. 20 per kg. If both type - I and type - II are mixed in the ratio of 2 : 3, then find the price per kg of the mixed variety.

19

19.50

18.50

18

19

19.50

18.50

18

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Alligation or Mixture problems
8 litres are drawn from a flask containing milk and then filledwith water. The operation is performed 3 more times. Theratio of the quantity of milk left and total solution is 81/625.How much milk the flask initially holds?

30 ltr

40 ltr

20 ltr

10 ltr

30 ltr

40 ltr

20 ltr

10 ltr

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Alligation or Mixture problems
A sum of Rs. 41 was divided among 50 boys and girls. Each boy gets 90 paise and a girl 65 paise. The number of boys is ?

34

14

16

36

34

14

16

36

ANSWER DOWNLOAD EXAMIANS APP

Alligation or Mixture problems
In what ratio should milk and water be mixed so that after selling the mixture at the cost price a profit of 50/3 % is made?

2:5

6:1

2:3

1:2

2:5

6:1

2:3

1:2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Method 1 to solve the equation.Let us assume Cost Price (C.P) of 1 liter milk be Y rupees.According to question,Selling Price (S.P) of 1 liter of mixture Y rupees. (Selling price should be same as Cost price)Profit = 50/3 %Let us assume Cost price of 1 Liter of Mixture of Water and Milk = CCost price of 1 Liter of Mixture of Water and Milk = Selling price of Mixture - Profit C = Y - C x 50/3%? C = Y - C x 50/3x100? C = Y - C x 1/3x2? C = Y - C/6? Y = C + C/6? Y = (6C + C)/6? Y = (6C + C)/6? Y = 7C/6? C = 6Y/7Since in Y rupees we will get 1 liter milk.Hence in 1 rupees we will get 1/Y liter milk.Hence in 6Y/7 rupees we will get 1 x 6Y/7 x Y liter milk.Hence in 6Y/7 rupees we will get 6/7 liter milk.We need 1 liter mixture of milk and water for sold on the same price, we need to mix the water.So water quantity in mixture = 1 - 6/7 = 1/7Ratio of Milk and water in mixture = quantity of Milk in Mixture/quantity of Water in MixtureRatio of Milk and water in mixture = 6/7 / 1/7Ratio of Milk and water in mixture = 6 x 7 / 7 Ratio of Milk and water in mixture = 6 / 1Ratio of Milk and water in mixture = 6 : 1Method 2 to solve the question.Let the original amount of milk be 1 liter and the cost price is 1 rupees per liter.Cost price of milk = 1 rupees.Selling price of Mixture = 1 rupees. When the milk is mix with x liters of water milk remaining is 1- x.Let us assume the cost price of milk in mixture is Y and given that the Sold Price is 1.we should use the Profit formula in algebra,Y + Y x 50/3 % = 1 Y + Y x 50/3 x 100 = 1Y + Y x /3 x 2 = 17Y/6 = 1Y = 6/7Y = 6/7 is the cost price of Mixture for 1 liter. Since water is free so there is not cost of water in mixture. So price of milk is 6/7 rs in mixture.Since as per question,In 1 rupees we will get 1 liter of milk.hence in 6/7 rupees we will get 1 x 6/7 = 6/7 liter of milk.Now we have to make 1 liter of mixture with water and milk.quantity of Water + Quantity of Milk = 1 literquantity of Water + 6/7 = 1 quantity of Water = 1 - 6/7 = (7 - 6)/7 quantity of Water = 1/7 Ratio of milk and Water = Quantity of Milk / quantity of Water Ratio of milk and Water = (6/7) / (1/7)Ratio of milk and Water = (6/7) x (7/1)Ratio of milk and Water = 6 x 7/ 7 x 1Ratio of milk and Water = 6 :1

Alligation or Mixture problems
A person covers a distance of 100 kms in 10 hours, partly by walking at 7 km/hr and rest by running at 12 km/hr. Find the distance covered in each part.

72 kms

108 kms

48 kms

124 kms

72 kms

108 kms

48 kms

124 kms

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Alligation or Mixture problems
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:

Rs. 175.50

Rs. 170

Rs. 180

Rs. 169.50

Rs. 175.50

Rs. 170

Rs. 180

Rs. 169.50

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Alligation or Mixture problems

Alligation or Mixture problems The cost of type - I rice is Rs. 15 per kg and type - II is Rs. 20 per kg. If both type - I and type - II are mixed in the ratio of 2 : 3, then find the price per kg of the mixed variety.

Alligation or Mixture problems 8 litres are drawn from a flask containing milk and then filledwith water. The operation is performed 3 more times. Theratio of the quantity of milk left and total solution is 81/625.How much milk the flask initially holds?

Alligation or Mixture problems A sum of Rs. 41 was divided among 50 boys and girls. Each boy gets 90 paise and a girl 65 paise. The number of boys is ?

Alligation or Mixture problems In what ratio should milk and water be mixed so that after selling the mixture at the cost price a profit of 50/3 % is made?

Alligation or Mixture problems A person covers a distance of 100 kms in 10 hours, partly by walking at 7 km/hr and rest by running at 12 km/hr. Find the distance covered in each part.

Alligation or Mixture problems Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:

Alligation or Mixture problems
The cost of type - I rice is Rs. 15 per kg and type - II is Rs. 20 per kg. If both type - I and type - II are mixed in the ratio of 2 : 3, then find the price per kg of the mixed variety.

Alligation or Mixture problems
8 litres are drawn from a flask containing milk and then filledwith water. The operation is performed 3 more times. Theratio of the quantity of milk left and total solution is 81/625.How much milk the flask initially holds?

Alligation or Mixture problems
A sum of Rs. 41 was divided among 50 boys and girls. Each boy gets 90 paise and a girl 65 paise. The number of boys is ?

Alligation or Mixture problems
In what ratio should milk and water be mixed so that after selling the mixture at the cost price a profit of 50/3 % is made?

Alligation or Mixture problems
A person covers a distance of 100 kms in 10 hours, partly by walking at 7 km/hr and rest by running at 12 km/hr. Find the distance covered in each part.

Alligation or Mixture problems
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be: