Machine Design The buckling load will be maximum for a column, if Both ends of the column are hinged One end of the column is hinged and the other end is free Both ends of the column are clamped One end of the column is clamped and the other end is free Both ends of the column are hinged One end of the column is hinged and the other end is free Both ends of the column are clamped One end of the column is clamped and the other end is free ANSWER DOWNLOAD EXAMIANS APP
Machine Design Eye bolts are used for Foundation purposes Lifting and transportation of machines and cubicles Absorbing shock and vibrations Transmission of power Foundation purposes Lifting and transportation of machines and cubicles Absorbing shock and vibrations Transmission of power ANSWER DOWNLOAD EXAMIANS APP
Machine Design Crowning on pulley helps To increase pulley life In decreasing the slip of the belt To keep the belt in centre on a pulley while it is in motion In increasing the slip of the belt To increase pulley life In decreasing the slip of the belt To keep the belt in centre on a pulley while it is in motion In increasing the slip of the belt ANSWER DOWNLOAD EXAMIANS APP
Machine Design The constant factor in case of R10 series of preferred numbers is 1.26 1.58 1.06 1.12 1.26 1.58 1.06 1.12 ANSWER DOWNLOAD EXAMIANS APP
Machine Design When an open coiled helical compression spring is subjected to an axial compressive load, the maximum shear stress induced in the wire is (where D = Mean diameter of the spring coil, d = Diameter of the spring wire, K = Wahl's stress factor, and W = Axial compressive load on the spring) (WD/ πd3) × K (2WD/ πd3) × K (4WD/ πd3) × K (8WD/ πd3) × K (WD/ πd3) × K (2WD/ πd3) × K (4WD/ πd3) × K (8WD/ πd3) × K ANSWER DOWNLOAD EXAMIANS APP
Machine Design A closely coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is τ. The half of the length of the spring if cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in new condition will be τ/2 τ 2 τ 4 τ τ/2 τ 2 τ 4 τ ANSWER DOWNLOAD EXAMIANS APP
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