Machine Design The buckling load will be maximum for a column, if Both ends of the column are hinged One end of the column is hinged and the other end is free Both ends of the column are clamped One end of the column is clamped and the other end is free Both ends of the column are hinged One end of the column is hinged and the other end is free Both ends of the column are clamped One end of the column is clamped and the other end is free ANSWER DOWNLOAD EXAMIANS APP
Machine Design A spring of stiffness 1000 N/m is stretched initially by 100 mm from the undeformed position. The work required to stretch it by another 100 mm is 7 N-m 10 N-m 15 N-m 5 N-m 7 N-m 10 N-m 15 N-m 5 N-m ANSWER DOWNLOAD EXAMIANS APP
Machine Design The design of the pressure vessel is based on None of these Longitudinal stress Hoop stress Longitudinal and hoop stress None of these Longitudinal stress Hoop stress Longitudinal and hoop stress ANSWER DOWNLOAD EXAMIANS APP
Machine Design If a spring is cut down into two springs, the stiffness of cut springs will be Same Double Half None of these Same Double Half None of these ANSWER DOWNLOAD EXAMIANS APP
Machine Design The face angle of a bevel gear is equal to Pitch angle + dedendum angle Pitch angle + addendum angle Pitch angle - addendum angle Pitch angle - dedendum angle Pitch angle + dedendum angle Pitch angle + addendum angle Pitch angle - addendum angle Pitch angle - dedendum angle ANSWER DOWNLOAD EXAMIANS APP
Machine Design When an open coiled helical compression spring is subjected to an axial compressive load, the maximum shear stress induced in the wire is (where D = Mean diameter of the spring coil, d = Diameter of the spring wire, K = Wahl's stress factor, and W = Axial compressive load on the spring) (WD/ πd3) × K (8WD/ πd3) × K (4WD/ πd3) × K (2WD/ πd3) × K (WD/ πd3) × K (8WD/ πd3) × K (4WD/ πd3) × K (2WD/ πd3) × K ANSWER DOWNLOAD EXAMIANS APP
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