Machine Design The velocity factor for ordinary cut gears operating at velocities up to 12.5 m/s is equal to 0.75/(0.75 + √v) 3/(3 + v) 4.5/(4.5 + v) 6/(6 + v) 0.75/(0.75 + √v) 3/(3 + v) 4.5/(4.5 + v) 6/(6 + v) ANSWER DOWNLOAD EXAMIANS APP
Machine Design When the belt is transmitting maximum power, the belt speed should be (Where, m = mass of belt per meter (kg/m) and Pmax = maximum permissible tension in belt (N)) √(3m /Pmax) √(Pmax / m) √(Pmax / 2m) √(Pmax / 3m) √(3m /Pmax) √(Pmax / m) √(Pmax / 2m) √(Pmax / 3m) ANSWER DOWNLOAD EXAMIANS APP
Machine Design The belt slip occurs due to Driving pulley too small Loose belt Heavy load Any one of the above Driving pulley too small Loose belt Heavy load Any one of the above ANSWER DOWNLOAD EXAMIANS APP
Machine Design The velocity of sliding __________ the distance of the point of contact from the pitch point. Does not depend upon Is inversely proportional to Is directly proportional to Is equal to cos φ multiplied by Does not depend upon Is inversely proportional to Is directly proportional to Is equal to cos φ multiplied by ANSWER DOWNLOAD EXAMIANS APP
Machine Design The fatigue life of a part can be improved by Electroplating Polishing Shot peening Coating Electroplating Polishing Shot peening Coating ANSWER DOWNLOAD EXAMIANS APP
Machine Design The yield point in static loading is __________ as compared to fatigue loading. Same None of these Lower Higher Same None of these Lower Higher ANSWER DOWNLOAD EXAMIANS APP
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