Machine Design The backlash for spur gears depends upon Tooth profile Module Pitch line velocity Both module and pitch line velocity Tooth profile Module Pitch line velocity Both module and pitch line velocity ANSWER DOWNLOAD EXAMIANS APP
Machine Design In cyclic loading, stress concentration is more serious in Ductile materials Brittle materials Brittle as well as ductile materials Elastic materials Ductile materials Brittle materials Brittle as well as ductile materials Elastic materials ANSWER DOWNLOAD EXAMIANS APP
Machine Design In a band and block brake, the ratio of tensions on the tight and slack sides of band is given by (where μ = Coefficient of friction between the blocks and the drum, θ = Semi-angle of each block subtending at the centre of drum, and n = Number of blocks) T₁/T₂ = (μθ)n T₁/T₂ = [(1 - μ tanθ)/ (1 + μ tanθ)]n T₁/T₂ = μθ × n T₁/T₂ = [(1 + μ tanθ)/ (1 - μ tanθ)]n T₁/T₂ = (μθ)n T₁/T₂ = [(1 - μ tanθ)/ (1 + μ tanθ)]n T₁/T₂ = μθ × n T₁/T₂ = [(1 + μ tanθ)/ (1 - μ tanθ)]n ANSWER DOWNLOAD EXAMIANS APP
Machine Design When the belt is transmitting maximum power, the belt speed should be (Where, m = mass of belt per meter (kg/m) and Pmax = maximum permissible tension in belt (N)) √(Pmax / 2m) √(Pmax / 3m) √(3m /Pmax) √(Pmax / m) √(Pmax / 2m) √(Pmax / 3m) √(3m /Pmax) √(Pmax / m) ANSWER DOWNLOAD EXAMIANS APP
Machine Design The velocity factor for ordinary cut gears operating at velocities up to 12.5 m/s is equal to 4.5/(4.5 + v) 0.75/(0.75 + √v) 6/(6 + v) 3/(3 + v) 4.5/(4.5 + v) 0.75/(0.75 + √v) 6/(6 + v) 3/(3 + v) ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given by Where m = mass of belt per meter (kg/m) v = belt velocity (m/s) f = coefficient of friction a = angle of wrap (radians) (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = e–ᶠα ANSWER DOWNLOAD EXAMIANS APP
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