Hydraulics and Fluid Mechanics in ME The atmospheric pressure at sea level is 10.3 m of water 103 kN/m2 All of these 760 mm of mercury 10.3 m of water 103 kN/m2 All of these 760 mm of mercury ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Buoyant force is The resultant force acting on a floating body The force necessary to maintain equilibrium of a submerged body The resultant force on a body due to the fluid surrounding it Equal to the volume of liquid displaced The resultant force acting on a floating body The force necessary to maintain equilibrium of a submerged body The resultant force on a body due to the fluid surrounding it Equal to the volume of liquid displaced ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME When the coefficient of discharge (Cd) is 0.623, then the general equation for discharge over a rectangular weir is 1.84(L - 0.1nH)H5/2 1.84(L - nH)H2 1.84(L - nH)H3 1.84(L - 0.1nH)H3/2 1.84(L - 0.1nH)H5/2 1.84(L - nH)H2 1.84(L - nH)H3 1.84(L - 0.1nH)H3/2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Power required (in watts) to drive a centrifugal pump is (where Hm = Manometric head in metres, w = Specific weight in N/m3, Q = Discharge of the pump in m3/s, and ηo = Overall efficiency of the pump) (w Q ηo) / Hm (w Hm) / (Q × ηo) (w Q) / (Hm × ηo) (w Hm Q) / ηo (w Q ηo) / Hm (w Hm) / (Q × ηo) (w Q) / (Hm × ηo) (w Hm Q) / ηo ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to empty the tank completely will be (2AH₁3/2)/(Cd × a√2g) (2A√H₁)/(Cd × a√2g) (2AH₁²)/(Cd × a√2g) (2AH₁)/(Cd × a√2g) (2AH₁3/2)/(Cd × a√2g) (2A√H₁)/(Cd × a√2g) (2AH₁²)/(Cd × a√2g) (2AH₁)/(Cd × a√2g) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to fan laws, at constant speed and capacity, the pressure and power vary Inversely as density Directly as the air or gas density As square of density Inversely as square root of density Inversely as density Directly as the air or gas density As square of density Inversely as square root of density ANSWER DOWNLOAD EXAMIANS APP
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