Engineering Thermodynamics The air standard efficiency of an Otto cycle is given by (where r = Compression ratio, and γ = Ratio of specific heats) 1 + rγ - 1 1 - (1/ rγ - 1) 1 - rγ - 1 1 + (1/ rγ - 1) 1 + rγ - 1 1 - (1/ rγ - 1) 1 - rγ - 1 1 + (1/ rγ - 1) ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics For a perfect gas, according to Boyle’s law (where P = Absolute pressure, V = Volume and T = Absolute temperature) P v = constant, if T is kept constant V/T = constant, if p is kept constant P/T = constant, if v is kept constant T/P = constant, if v is kept constant P v = constant, if T is kept constant V/T = constant, if p is kept constant P/T = constant, if v is kept constant T/P = constant, if v is kept constant ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics One kg of carbon monoxide requires 4/7 kg of oxygen and produces 11/3 kg of carbon dioxide gas 8/3 kg of carbon monoxide gas 11/7 kg of carbon dioxide gas 7/3 kg of carbon monoxide gas 11/3 kg of carbon dioxide gas 8/3 kg of carbon monoxide gas 11/7 kg of carbon dioxide gas 7/3 kg of carbon monoxide gas ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The compression ratio is the ratio of Swept volume to total volume Total volume to clearance volume Swept volume to clearance volume Total volume to swept volume Swept volume to total volume Total volume to clearance volume Swept volume to clearance volume Total volume to swept volume ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The value of the product of molecular weight and the gas characteristic constant for all the gases in M.K.S. unit is 29.27 kgfm/mol °K 8314 kgfm/mol °K 427 kgfm/mol °K 848 kgfm/mol °K 29.27 kgfm/mol °K 8314 kgfm/mol °K 427 kgfm/mol °K 848 kgfm/mol °K ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The kinetic energy per kg molecule of any gas at absolute temperature T is equal to (where Ru = Universal gas constant) 1.5 Ru × T 2 Ru × T Ru × T 3 Ru × T 1.5 Ru × T 2 Ru × T Ru × T 3 Ru × T ANSWER DOWNLOAD EXAMIANS APP
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