Engineering Thermodynamics Work done in a free expansion process is Positive Zero Maximum Minimum Positive Zero Maximum Minimum ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Work-done during adiabatic expansion is given by (where p1 v1, T1 = Pressure, volume and temperature for the initial condition of gas, p2, v2, T2 = Corresponding values for the final condition of gas, R = Gas constant, and γ = Ratio of specific heats) (p1 v1 - p2, v2)/(γ - 1) [m R (T1 - T2)] /(γ - 1) [m R T1/(γ - 1)][1 - (p2, v2 /p1 v1)] All of these (p1 v1 - p2, v2)/(γ - 1) [m R (T1 - T2)] /(γ - 1) [m R T1/(γ - 1)][1 - (p2, v2 /p1 v1)] All of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics One Joule (J) is equal to 10 kN-m/s 1 N-m 10 N-m/s 1 kN-m 10 kN-m/s 1 N-m 10 N-m/s 1 kN-m ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Zeroth law of thermodynamics Deals with conversion of mass and energy States that if two systems are both in equilibrium with a third system, they are in thermal equilibrium with each other Deals with reversibility and irreversibility of process Deals with heat engines Deals with conversion of mass and energy States that if two systems are both in equilibrium with a third system, they are in thermal equilibrium with each other Deals with reversibility and irreversibility of process Deals with heat engines ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The heat absorbed or rejected by the working substance is given by (where ds = Increase or decrease of entropy, T = Absolute temperature, and dQ = Heat absorbed or rejected) None of the listed here δQ = T/ds δQ = T.ds dQ = ds/T None of the listed here δQ = T/ds δQ = T.ds dQ = ds/T ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics In S. I. units, the value of the universal gas constant is 8314 J/kg mole-K 8.314 J/kg mole-K 83.14 J/kg mole-K 831.4 J/kg mole-K 8314 J/kg mole-K 8.314 J/kg mole-K 83.14 J/kg mole-K 831.4 J/kg mole-K ANSWER DOWNLOAD EXAMIANS APP
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