Engineering Thermodynamics A mixture of gas expands from 0.03 m3 to 0.06 m3 at a constant pressure of 1 MPa and absorbs 84 kJ of heat during the process. The change in internal energy of the mixture is 54 kJ 84 kJ 114 kJ 30 kJ 54 kJ 84 kJ 114 kJ 30 kJ ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics General gas equation is PV=mRT PV = C PV=KiRT PV=nRT PV=mRT PV = C PV=KiRT PV=nRT ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The value of 1 mm of Hg is equal to 13.33 N/m2 1.333 N/m2 133.3 N/m2 1333 N/m2 13.33 N/m2 1.333 N/m2 133.3 N/m2 1333 N/m2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Brayton cycle consists' of following four processes Two isentropic, one constant volume and one constant pressure Two isentropic and two constant pressures Two isentropic and two constant volumes Two isothermal and two isentropic Two isentropic, one constant volume and one constant pressure Two isentropic and two constant pressures Two isentropic and two constant volumes Two isothermal and two isentropic ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The value of gas constant (R) in S. I. units is 0.287 J/kgK 2.87 J/kgK 287 J/kgK 28.7 J/kgK 0.287 J/kgK 2.87 J/kgK 287 J/kgK 28.7 J/kgK ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The gas constant (R) is equal to the Product of two specific heats Ratio of two specific heats Difference of two specific heats Sum of two specific heats Product of two specific heats Ratio of two specific heats Difference of two specific heats Sum of two specific heats ANSWER DOWNLOAD EXAMIANS APP
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