Engineering Thermodynamics When the gas is heated at constant volume, the heat supplied Both (A) and (B) None of these Does some external work during expansion Increases the internal energy of the gas and increases the temperature of the gas Both (A) and (B) None of these Does some external work during expansion Increases the internal energy of the gas and increases the temperature of the gas ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics If a gas is heated against a pressure, keeping the volume constant, then work done will be equal to Zero Anywhere between zero and infinity +ve -ve Zero Anywhere between zero and infinity +ve -ve ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Zeroth law of thermodynamics Deals with conversion of mass and energy Deals with heat engines Deals with reversibility and irreversibility of process States that if two systems are both in equilibrium with a third system, they are in thermal equilibrium with each other Deals with conversion of mass and energy Deals with heat engines Deals with reversibility and irreversibility of process States that if two systems are both in equilibrium with a third system, they are in thermal equilibrium with each other ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The energy of molecular motion appears as Heat Surface tension Friction Potential energy Heat Surface tension Friction Potential energy ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics If a system after undergoing a series of processes, returns to the initial state then Sum of heat and work transfer will be zero Its entropy will change due to irreversibility Process is executed in closed system cycle Process is thermodynamically in equilibrium Sum of heat and work transfer will be zero Its entropy will change due to irreversibility Process is executed in closed system cycle Process is thermodynamically in equilibrium ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Work-done during adiabatic expansion is given by (where p1 v1, T1 = Pressure, volume and temperature for the initial condition of gas, p2, v2, T2 = Corresponding values for the final condition of gas, R = Gas constant, and γ = Ratio of specific heats) All of these [m R T1/(γ - 1)][1 - (p2, v2 /p1 v1)] (p1 v1 - p2, v2)/(γ - 1) [m R (T1 - T2)] /(γ - 1) All of these [m R T1/(γ - 1)][1 - (p2, v2 /p1 v1)] (p1 v1 - p2, v2)/(γ - 1) [m R (T1 - T2)] /(γ - 1) ANSWER DOWNLOAD EXAMIANS APP
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