RCC Structures Design The advantage of reinforced concrete, is due to Monolithic character All listed here Fire-resisting and durability Economy because of less maintenance cost Monolithic character All listed here Fire-resisting and durability Economy because of less maintenance cost ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum shear stress at the end of a simply supported R.C.C. beam of 16 m effective span is 10 kg/cm², the length of the beam having nominal reinforcement, is 12 cm 6 cm 10 cm 8 cm 12 cm 6 cm 10 cm 8 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For a continuous floor slab supported on beams, the ratio of end span length and intermediate span length, is 0.6 0.7 0.8 0.9 0.6 0.7 0.8 0.9 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For a ribbed slab All listed here Overall depth of the slab shall not exceed four times the breadth of the rib Width of the rib shall not be less than 7.5 cm Clear spacing between ribs shall not be greater than 4.5 cm All listed here Overall depth of the slab shall not exceed four times the breadth of the rib Width of the rib shall not be less than 7.5 cm Clear spacing between ribs shall not be greater than 4.5 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the shear stress in a R.C.C. beam is Greater than 20 kg/cm², the size of the section is changed Greater than 4 kg/cm², but less than 20 kg/cm², shear reinforcement is provided All of these Equal or less than 5 kg/cm², no shear reinforcement is provided Greater than 20 kg/cm², the size of the section is changed Greater than 4 kg/cm², but less than 20 kg/cm², shear reinforcement is provided All of these Equal or less than 5 kg/cm², no shear reinforcement is provided ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If Sb, is the average bond stress on a bar of diameter ‘d’ subjected to maximum stress ‘t’, the length of the embedment ‘l’ is given by l = dt/4Sb l = dt/Sb l = dt/3Sb l = dt/2Sb l = dt/4Sb l = dt/Sb l = dt/3Sb l = dt/2Sb ANSWER DOWNLOAD EXAMIANS APP
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