RCC Structures Design The shear reinforcement in R.C.C. is provided to resist Horizontal shear Diagonal compression Vertical shear Diagonal tension Horizontal shear Diagonal compression Vertical shear Diagonal tension ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to load factor method, the permissible load ‘W’ on a short column reinforced with longitudinal bars and lateral stirrups, is Stress in steel × area of steel Stress in concrete × area of concrete + Stress in steel × area of steel None of these Stress in concrete × area of concrete Stress in steel × area of steel Stress in concrete × area of concrete + Stress in steel × area of steel None of these Stress in concrete × area of concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p₁ and p₂ are mutually perpendicular principal stresses acting on a soil mass, the normal stress on any plane inclined at angle θ° to the principal plane carrying the principal stress p₁, is: [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If permissible working stresses in steel and concrete are respectively 1400 kg/cm² and 80 kg/cm² and modular ratio is 18, in a beam reinforced in tension side and of width 30 cm and having effective depth 46 cm, the lever arms of the section, is 38 cm 40 cm 37 cm 39 cm 38 cm 40 cm 37 cm 39 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For initial estimate for a beam design, the width is assumed 1/30th of span 1/25th of span 1/15th of span 1/20th of span 1/30th of span 1/25th of span 1/15th of span 1/20th of span ANSWER DOWNLOAD EXAMIANS APP
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