RCC Structures Design The shear reinforcement in R.C.C. is provided to resist Diagonal tension Vertical shear Diagonal compression Horizontal shear Diagonal tension Vertical shear Diagonal compression Horizontal shear ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If a rectangular pre-stressed beam of an effective span of 5 meters and carrying a total load 3840 kg/m, is designed by the load balancing method, the central dip of the parabolic tendon should be 20 cm 5 cm 10 cm 15 cm 20 cm 5 cm 10 cm 15 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the ratio of long and short spans of a two way slab with corners held down is r, the actual reduction of B.M. is given by (5/6) (r²/1 + r²) M (5/6) (r²/1 + r³) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r⁴) M (5/6) (r²/1 + r²) M (5/6) (r²/1 + r³) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r⁴) M ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The thickness of the topping of a ribbed slab, varies between 5 cm to 8 cm 3 cm to 5 cm 12 cm to 15 cm 8 cm to 10 cm 5 cm to 8 cm 3 cm to 5 cm 12 cm to 15 cm 8 cm to 10 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a slab, the pitch of the main reinforcement should not exceed its effective depth Three times Four times Five times Two times Three times Four times Five times Two times ANSWER DOWNLOAD EXAMIANS APP
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