Hydraulics and Fluid Mechanics in ME Rain drops are spherical because of viscosity air resistance atmospheric pressure surface tension forces viscosity air resistance atmospheric pressure surface tension forces ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Manometer is used to measure atmospheric pressure pressure in pipes, channels etc very low pressure difference of pressure between two points atmospheric pressure pressure in pipes, channels etc very low pressure difference of pressure between two points ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The pressure at a point 4 m below the free surface of water is 29.24 kPa 19.24 kPa 39.24 kPa 49.24 kPa 29.24 kPa 19.24 kPa 39.24 kPa 49.24 kPa ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Froude number is significant in Supersonics, as with projectile and jet propulsion All of the listed here Simultaneous motion through two fluids where there is a surface of discontinuity, gravity forces, and wave making effect, as with ship's hulls Full immersion or completely enclosed flow, as with pipes, aircraft wings, nozzles etc. Supersonics, as with projectile and jet propulsion All of the listed here Simultaneous motion through two fluids where there is a surface of discontinuity, gravity forces, and wave making effect, as with ship's hulls Full immersion or completely enclosed flow, as with pipes, aircraft wings, nozzles etc. ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In an internal mouthpiece, if the jet after contraction does not touch the sides of the mouthpiece, then the mouthpiece is said to be Partially running full Partially running free Running free Running full Partially running full Partially running free Running free Running full ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L.√2g [H12 - Ha2] ANSWER DOWNLOAD EXAMIANS APP
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