Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 2 minute 48 seconds 4 minute 48 seconds 3 minute 48 seconds 1 minute 48 seconds 2 minute 48 seconds 4 minute 48 seconds 3 minute 48 seconds 1 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
Problems on H.C.F and L.C.M Three friends Raju , Ramesh and Sunil start running around a circular stadium and complete a single round in 24 s, 36 s and 40 s, respectively. After how many minutes will they meet against at the sta 8 minutes 5 minutes 6 minutes 7 minutes 8 minutes 5 minutes 6 minutes 7 minutes ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 24 = 3 × 2 × 2 × 2 = 3 × 2³ 36 = 3 × 3 × 2 × 2 = 3² × 2²and 40 = 2 × 2 × 2 × 5 = 5¹ × 23 LCM of 24, 36 and 40 = 3² × 2³ × 5 = 9 × 8 × 5 = 360Hence, they will meet again at the starting point after 360 s, i.e., 6 min
Problems on H.C.F and L.C.M What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder? 123 116 121 112 123 116 121 112 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 27 25 23 21 27 25 23 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
Problems on H.C.F and L.C.M The HCF of 2 numbers is 11 and LCM is 693.If one of numbers is 77.find the other number ? 100 98 99 97 100 98 99 97 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers= HCF x LCM 77 x a = 11 x 693Other number a = (11×693)/77 = 99.
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