DNA Structure and Replication Nucleosome is an octamer of four histones with H1 protein an octamer of four histones without H1 protein an hexamer of three histones with H1 protein an hexamer of three histones without H1 protein an octamer of four histones with H1 protein an octamer of four histones without H1 protein an hexamer of three histones with H1 protein an hexamer of three histones without H1 protein ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication The nicks or gaps between Okazaki fragments are eventually sealed by gyrase RNA ligase DNA ligase polymerase gyrase RNA ligase DNA ligase polymerase ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication The chromosomal DNA complexes with four types of histone as H1, H2A, H3 and H4 five types of histone as H1, H2A, H2B, H3 and H4 two types of histone as H1 and H4 three types of histone as H1, H2A and H4 four types of histone as H1, H2A, H3 and H4 five types of histone as H1, H2A, H2B, H3 and H4 two types of histone as H1 and H4 three types of histone as H1, H2A and H4 ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Replication in E. coli is initiated by the generation of short RNA primers using both (a) and (b) RNA polymerase reverse transcriptase primase both (a) and (b) RNA polymerase reverse transcriptase primase ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication The overall conclusion of the Hershey-Chase experiment was that phage DNA was similar to bacterial DNA DNA was responsible for heredity the ratio of Adenine to thymine was always the same proteins and DNA were responsible for heredity phage DNA was similar to bacterial DNA DNA was responsible for heredity the ratio of Adenine to thymine was always the same proteins and DNA were responsible for heredity ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Which of the following is used to determine the appropriate stringency (Wallace rule)? Tm = 69.3° + 0.41 (%)G+C -650/1 Tm = 4 x (No.of G:C base pair) + 2 x (No.of A:T base pair) Tm = 4 x (No.of A:T base pair) + 2 x (No.of G:C base pair) Tm = 2 x (No.of G:C base pair) + 4 x (No.of A:T base pair) Tm = 69.3° + 0.41 (%)G+C -650/1 Tm = 4 x (No.of G:C base pair) + 2 x (No.of A:T base pair) Tm = 4 x (No.of A:T base pair) + 2 x (No.of G:C base pair) Tm = 2 x (No.of G:C base pair) + 4 x (No.of A:T base pair) ANSWER DOWNLOAD EXAMIANS APP
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