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Engineering Mechanics

Engineering Mechanics
Moment of inertia of a circular section about an axis perpendicular to the section is

πd3/16
πd4/32
πd4/64
πd3/32

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Engineering Mechanics
The periodic time (T) is given by (where, ω = Angular velocity of particle in rad/s.)

π/ω
2π/ω
2π × ω
ω/2π

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Engineering Mechanics
A ladder is resting on a smooth ground and leaning against a rough vertical wall. The force of friction will act

Towards the wall at its upper end
Upward at its upper end
Away from the wall at its upper end
Downward at its upper end

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Engineering Mechanics
If a number of forces are acting at a point, their resultant will be inclined at an angle 'θ' with the horizontal, such that

tanθ = √(ΣV + ΣH)
tanθ = ΣV/ΣH
tanθ = ΣH/ΣV
tanθ = ΣV × ΣH

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Engineering Mechanics
A force while acting on a body may

All of these
Balance the forces, already acting on it
Change its motion
Give rise to the internal stresses in it

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Engineering Mechanics
On the ladder resting on the ground and leaning against a smooth vertical wall, the force of friction will be

Zero at its upper end
Downwards at its upper end
Perpendicular to the wall at its upper end
Upwards at its upper end

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MORE MCQ ON Engineering Mechanics

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