Engineering Mechanics Moment of inertia of a circular section about an axis perpendicular to the section is πd4/32 πd4/64 πd3/32 πd3/16 πd4/32 πd4/64 πd3/32 πd3/16 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Coefficient of friction depends upon None of these Area of contact only Nature of surface only Both (A) and (B) None of these Area of contact only Nature of surface only Both (A) and (B) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The periodic time of one oscillation for a simple pendulum is (where l = Length of the pendulum.) (1/2π). √(g/l) (1/2π). √(l/g) 2π. √(l/g) None of these (1/2π). √(g/l) (1/2π). √(l/g) 2π. √(l/g) None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity of a particle (v) moving with simple harmonic motion, at any instant is given by (where, r = Amplitude of motion, and y = Displacement of the particle from mean position.) ω².√(r² - y²) ω.√(y² - r²) ω².√(y² - r²) ω.√(r² - y²) ω².√(r² - y²) ω.√(y² - r²) ω².√(y² - r²) ω.√(r² - y²) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = Ah2 / IG IP = IG + Ah2 IP = IG / Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG / Ah2 IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The linear velocity of a body rotating at ω rad/s along a circular path of radius r is given by ω².r ω.r ω/r ω²/r ω².r ω.r ω/r ω²/r ANSWER DOWNLOAD EXAMIANS APP
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