RCC Structures Design Minimum spacing between horizontal parallel reinforcement of the same size should not be less than One diameter 3 diameters 3.5 diameters 2.5 diameters One diameter 3 diameters 3.5 diameters 2.5 diameters ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pile of length ‘L’ carrying a uniformly distributed load ‘W’ per metre length is suspended at two points, the maximum, B.M. at the centre of the pile or at the points of suspension, is WL²/24 WL²/47 WL/8 WL²/16 WL²/24 WL²/47 WL/8 WL²/16 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to load factor method, the permissible load ‘W’ on a short column reinforced with longitudinal bars and lateral stirrups, is Stress in steel × area of steel None of these Stress in concrete × area of concrete + Stress in steel × area of steel Stress in concrete × area of concrete Stress in steel × area of steel None of these Stress in concrete × area of concrete + Stress in steel × area of steel Stress in concrete × area of concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For stairs spanning horizontally, the minimum waist provided is 12 cm 8 cm 6 cm 4 cm 12 cm 8 cm 6 cm 4 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Shear force × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Shear force × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If T and R are tread and rise respectively of a stair, then 2R + T = 60 R + 2T = 60 R + 2T= 30 2R + T = 30 2R + T = 60 R + 2T = 60 R + 2T= 30 2R + T = 30 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS