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Electrical Machines

Electrical Machines
Maximum power developed depends on

 both 1and 2
 load angle
 voltage
 reactance

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Electrical Machines
In a synchronous machine, if φ is the flux per pole and f is the frequency of the emf induced E then

 E ∝ f/φ
 E ∝ 1/(φf)
 E ∝ φf
 E ∝ φ/f

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Electrical Machines
If iron loss and full load copper loss of any transformer are denoted by Pi and Pc, then the load corresponding to maximum efficiency is given by

 (Pi / Pc) × full Load.
 (Pi / Pc)2 × full Load.
 (Pi / Pc)1.6 × full Load.
  (Pi / Pc)0.5 × Full Load.

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Electrical Machines
Two single-phase alternators operating in parallel have induced EMFs on open circuit of 230∠0° and 230∠10° volts and respective reactance of j2 Ω j3 Ω calculate the terminal voltage

  223.V.
 150 V.
 200 V.
 300 V.

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Electrical Machines
A 2 KVA transformer has iron loss of 150 W and full load copper loss of 250 W. The maximum efficiency of the transformer would occur when the total loss is

 250 W
 500 W
 400W
 300 W

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Electrical Machines
The supply voltage to an induction motor is reduced by 10%. By what percentage, approximately, will the maximum torque decrease?

 19%
 10%
 5%
 40%

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