Electrical Machines Series booster is a separately excited DC generator. permanent magnet DC generator. shunt wound DC generator. series wound DC generator. separately excited DC generator. permanent magnet DC generator. shunt wound DC generator. series wound DC generator. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines If the excitation of the synchronous generator fails, it acts as a/an synchronous motor. synchronous generator. induction motor. induction generator. synchronous motor. synchronous generator. induction motor. induction generator. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines During no load test, an induction motor draws power for core loss and windage and friction loss. only for the small copper loss. for core loss and copper loss. for copper loss and windage friction loss. for core loss and windage and friction loss. only for the small copper loss. for core loss and copper loss. for copper loss and windage friction loss. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A DC series motor is accidentally connected to single phase ac supply voltage. The torque produced will be None of these oscillating steady and unidirectional pulsating and unidirectional None of these oscillating steady and unidirectional pulsating and unidirectional ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A belt-driven cumulatively-compound dc generator is delivering power to the dc mains. If the Belt snaps then the machine will run as a differentially compounded motor in the opposite direction cumulative compounded motor in opposite direction cumulative compounded motor in the same direction differentially compounded motor in the same direction differentially compounded motor in the opposite direction cumulative compounded motor in opposite direction cumulative compounded motor in the same direction differentially compounded motor in the same direction ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines For P pole machine relation between electrical degrees and mechanical degrees is θelec = P/2*θmech θelec = 2/P*θmech θelec = θmech θelec = 4/P*θmech θelec = P/2*θmech θelec = 2/P*θmech θelec = θmech θelec = 4/P*θmech ANSWER DOWNLOAD EXAMIANS APP
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