Surveying Limiting gradient for locating the base line on evenly-sloping ground, is 1 in 8 1 in 10 1 in 6 1 in 12 1 in 8 1 in 10 1 in 6 1 in 12 ANSWER DOWNLOAD EXAMIANS APP
Surveying If θ and δ be the latitude of an observer and declination of a heavenly body respectively, the upper culmination of the body will be south of zenith if its zenith distance, is θ - δ ½ (θ - δ) δ - θ θ + δ θ - δ ½ (θ - δ) δ - θ θ + δ ANSWER DOWNLOAD EXAMIANS APP
Surveying Right ascension of a heavenly body is its equatorial angular distance measured Eastward from the first point of Libra Westward from the first point of Aeries Eastward from the first point of Aeries Westward from the first point of Libra Eastward from the first point of Libra Westward from the first point of Aeries Eastward from the first point of Aeries Westward from the first point of Libra ANSWER DOWNLOAD EXAMIANS APP
Surveying For adjusting a quadrilateral whose both the diagonals are observed, the equations of conditions involved, are Three angle equations and one side equation Two angle equations and two side equations None of these One angle equation and three side equations Three angle equations and one side equation Two angle equations and two side equations None of these One angle equation and three side equations ANSWER DOWNLOAD EXAMIANS APP
Surveying For a well-conditioned triangle, no angle should be less than 45° 30° 60° 20° 45° 30° 60° 20° ANSWER DOWNLOAD EXAMIANS APP
Surveying If the equatorial distance between two meridians is 100 km, their distance at 60° latitude will be 600 km 800 km 1000 km 500 km 600 km 800 km 1000 km 500 km ANSWER DOWNLOAD EXAMIANS APP
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